<u><em>Its Going to Be Table B! Good Luck :)⇔</em></u>
4) x=16
Vertical angles have equal angles when two lines intersect, which they do in this case.
3x-3=2x+13
Solve for x:
x=16
5) 34 degrees
Lines AK and MJ bisect each other perpendicually, so <ADJ is 90 degrees.
4x+3x-8=90
7x-8=90
7x=98
x=14
<CDJ=3x-8
=3(14)-8
=34 degrees
Hope this helps :)
To write an equation in standard form, move each term to the left side of the equation and simplify.
ax2+bx+c = 0ax2+bx+c = 0
Move all the expressions to the left side of the equation.
−17−8x2−4x+3x2 = 0-17-8x2-4x+3x2 = 0
Add −8x2-8x2 and 3x23x2.
−17−5x2−4x = 0-17-5x2-4x = 0
Reorder the polynomial.
5x2+4x+17 = 0
Step-by-step explanation:
I hope this helped-
Answer:
This question needs a step to step long explanation.
You probably jsut need to use law of cosines in order to solve for angle A

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