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dlinn [17]
3 years ago
10

*ANSWER ASAP* {WILL GIVE BRAINLIEST} Refer to the equation 3x - 2y = -18

Mathematics
1 answer:
Andrej [43]3 years ago
5 0

m=3/2 is the answer for the equation

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Find the Solution for x + y = 5 and -2x + y = 2<br> х<br> Type your answer below with no spaces
Burka [1]

x + y = 5..........(I)

or,x=5-y

-2x + y = 2..........(II)

replacing x=5-y in equation (II),.we get ...

-2(5-y)+y=2

-10+2y+y=2

or,3y=12

y=4

now.,,

putting y=4 in equation (I)

x+4=5

x=5-4

x=1

hence x=1

3 0
2 years ago
How to solve -6x-5y=18<br> -5×+2y=22
Orlov [11]
-5 x 2y = 22
2y = 22 / -5 which is -4.4
y = -2.2
Substitute:
-6x + 11 = 18
-6x = 7
x = 7 / -6
6 0
3 years ago
8
ss7ja [257]

Answer:

how long the question is oh god

7 0
4 years ago
Can u pls help me with this question
Anastasy [175]

Answer:

D

Step-by-step explanation:

$65-$39=$26 increase

$26/$39=.6667 or 66.67%

3 0
3 years ago
A simple random sample of size nequals=8181 is obtained from a population with mu equals 77μ=77 and sigma equals 27σ=27. ​(a) De
ivanzaharov [21]

Answer:

a) P(\bar X>81.5)=1-0.933=0.067

b) P(\bar X

c) P(73.4  

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Let X the random variable that represent interest on this case, and for this case we know the distribution for X is given by:

X \sim N(\mu=77,\sigma=27)  

And let \bar X represent the sample mean, the distribution for the sample mean is given by:

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})

On this case  \bar X \sim N(77,\frac{27}{\sqrt{81}})

Part a

We want this probability:

P(\bar X>81.5)=1-P(\bar X

The best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

If we apply this formula to our probability we got this:

P(\bar X >81.5)=1-P(Z

P(\bar X>81.5)=1-0.933=0.067

Part b

We want this probability:

P(\bar X\leq 69.5)

If we apply the formula for the z score to our probability we got this:

P(\bar X \leq 69.5)=P(Z\leq \frac{69.5-77}{\frac{27}{\sqrt{81}}})=P(Z

P(\bar X\leq 69.5)=0.0062

Part c

We are interested on this probability

P(73.4  

If we apply the Z score formula to our probability we got this:

P(73.4

=P(\frac{73.4-77}{\frac{27}{\sqrt{81}}}

And we can find this probability on this way:

P(-1.2

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(-1.2

3 0
4 years ago
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