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Ludmilka [50]
3 years ago
11

On a regional map, the scale shows that 2 cm on the map = 10 actual miles. The actual distance from Forest Hills to Plainville i

s 74 miles. How far apart are these cities on the map?
A.)5 cm
B.)7.4 cm
C.)8 cm
D).14.8 cm
Mathematics
1 answer:
Gelneren [198K]3 years ago
4 0

Answer:

D      

Step-by-step explanation:

if every 2 cm on the map=10 miles, I can use my basic knowledge to find out how many cm will equal 70, in this case I can multiply 7 on both sides to find out how many cm on the map will equal 70, so 2(7)cm=10(7)mi will result as 14cm=70mi. Even though the answer seems pretty clear I can round my answer closer to 2 or I can double check by dividing 74 by 10=7.4 times the 2 cm which gets me 14.8.

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Answer:

I think it's $12.80 but I might be wrong.

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3 years ago
WHICH IS BIGGER 3/10 OR 3/5
Zolol [24]
It is 3/10 because 10 is bigger than 5
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Whats 4x/2x if x=infinity?
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Find the equation for the line that passes through the point (5,-3), and that is perpendicular to the line with the equation y-1
8090 [49]

Answer:

y+3=-4(x-5)

Explanation:

Part A

Given the line:

y-1=\frac{1}{4}(x-2)

We want to find the equation of a perpendicular line that passes through the point (5,-3),

First, determine the slope of the perpendicular line.

Comparing the given line with the slope-point form:

\begin{gathered} y-y_1=m(x-x_1) \\ \implies\text{Slope},m=\frac{1}{4} \end{gathered}

By definition, two lines are perpendicular if the product of their slopes is -1.

Let the slope of the perpendicular line = n

\begin{gathered} \implies\frac{1}{4}n=-1 \\ n=-4 \end{gathered}

Thus, using a slope of -4 and a point (5,-3), we find the equation of the line.

\begin{gathered} y-y_1=m(x-x_1) \\ y-(-3)=-4(x-5) \\ y+3=-4(x-5) \end{gathered}

The equation of the perpendicular line in the slope-point form is:

y+3=-4(x-5)

Part B

In order to graph the line, first, find two points on the line.

When x=0

\begin{gathered} y+3=-4(0-5) \\ y+3=20 \\ y=20-3=17 \\ \implies(0,17) \end{gathered}

When y=1

\begin{gathered} 1+3=-4(x-5) \\ 4=-4(x-5) \\ \frac{4}{-4}=x-5 \\ -1=x-5 \\ x=5-1=4 \\ \implies(4,1) \end{gathered}

Join the points (0,17) and (4,1) as shown in the graph below:

3 0
1 year ago
Which of the following graphs is described by the function given below? y = 2x 2 + 6x + 3
Alla [95]

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

y=2x^{2}+6x+3

This is the equation of a vertical parabola open up

The vertex is a minimum

Convert to vertex form

Complete squares

y-3=2x^{2}+6x

Factor the leading coefficient

y-3=2(x^{2}+3x)

y-3+4.5=2(x^{2}+3x+2.25)

y+1.5=2(x^{2}+3x+2.25)

Rewrite as perfect squares

y+1.5=2(x+1.5)^{2}

The vertex is the point (-1.5,-1.5)

Find the zeros of the function

For y=0

2(x+1.5)^{2}=1.5

(x+1.5)^{2}=3/4

square root both sides

x+\frac{3}{2} =(+/-)\frac{\sqrt{3}}{2}

x=-\frac{3}{2}(+/-)\frac{\sqrt{3}}{2}

x=-\frac{3}{2}(+)\frac{\sqrt{3}}{2}=\frac{-3+\sqrt{3}}{2}=-0.634

x=-\frac{3}{2}(-)\frac{\sqrt{3}}{2}=\frac{-3-\sqrt{3}}{2}=-2.366

Find the y-intercept

For x=0

y=3

The y-intercept is the point (0,3)

therefore

The graph in the attached figure

8 0
3 years ago
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