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Ira Lisetskai [31]

3 years ago

6

I plugged in 4 for the derivative function but I’m getting the wrong answer?

1 answer:

Georgia [21]3 years ago

8 0

Answer:

8.6615988

Step-by-step explanation:

f(x) = 3 sin (x) / ( 1 + cos x)

To find the derivative bottom * d/ dx top - top d/dx bottom all over the bottom squared

d/dx = 3 ( ( 1 + cos x) cos x - sin x( - sin x)) / ( 1 + cos x) ^2

= 3 ( cos x + cos ^2 x + sin ^2 x) / ( 1 + cos x) ^2

= 3 ( 1 + cos x) / ( 1 + cos x) ^2

= 3 / ( 1 + cos x)

Let x = 4

3 / ( 1 + cos 4)

Assuming x is in radians

3/.346356

8.6615988

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PLEASE HELP ME WITH MATH PLEASE

Yuki888 [10]

Answer:

$a=250$

$b=10$

Step-by-step explanation:

$a=\frac{5x^2}{2}=\frac{5(10)^2}{2}=\frac{5(100)}{2}=\frac{500}{2}=250$

$b=\frac{2x^2(x-5)}{10x}=\frac{2(10)^2(10-5)}{10(10)}=\frac{2(100)(5)}{100}=2(5)=10$

7 0

3 years ago

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Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.

loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>

$x^ax^b = x^{(a+b)}$
$\dfrac{x^a}{x^b} = x^{(a-b)}$
$(a^a)^b =x^{(a\times b)}$
$(xy)^a = x^ay^a$

$x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4$

The solution of the expression is $\dfrac{4x^4}{y^6}$ .

<h2>Explanation</h2>

Given to us

$(16x^8y^{12})^{\frac{1}{2}}$

Solution

We know that 16 can be reduced to $2^4$ ,

$=(2^4x^8y^{12})^{\frac{1}{2}}$

Using identity $(xy)^a = x^ay^a$ ,

$=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}$

Using identity $(a^a)^b =x^{(a\times b)}$ ,

$=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})$

Solving further

$=2^2x^4y^{-6}$

Using identity $\dfrac{x^a}{x^b} = x^{(a-b)}$ ,

$=\dfrac{2^2x^4}{y^6}$

$=\dfrac{4x^4}{y^6}$

Hence, the solution of the expression is $\dfrac{4x^4}{y^6}$ .

Learn more about Exponentiation:

brainly.com/question/2193820

8 0

2 years ago

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Phantasy [73]

Your answer is y=-3/4x+7 because when you find rise over run it's -9/8 which rounds down to -3/4 which is your slope and 7 is the

5 0

4 years ago

Help with Algebra 2: 1. <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B7%5D%7Bx%5E5%7D%20%7D%7B%5Csqrt%5B4%5D%7Bx%5E2%7D%

Mars2501 [29]

Answer:

See explanation

Step-by-step explanation:

1. Given the expression

$\dfrac{\sqrt[7]{x^5} }{\sqrt[4]{x^2} }$

Note that

$\sqrt[7]{x^5}=x^{\frac{5}{7}} \\ \\\sqrt[4]{x^2}=x^{\frac{2}{4}}=x^{\frac{1}{2}}$

When dividing $\sqrt[7]{x^5}$ by $\sqrt[4]{x^2},$ we have to subtract powers (we cannot subtract 4 from 7, because then we get another expression), so

$\dfrac{5}{7}-\dfrac{2}{4}=\dfrac{5}{7}-\dfrac{1}{2}=\dfrac{5\cdot 2-1\cdot 7}{14}=\dfrac{3}{14}$

and the result is $x^{\frac{3}{14}}=\sqrt[14]{x^3}$

2. Given equation $3\sqrt[4]{(x-2)^3} -4=20$

Add 4:

$3\sqrt[4]{(x-2)^3} -4+4=20+4\\ \\3\sqrt[4]{(x-2)^3}=24$

Divide by 3:

$\sqrt[4]{(x-2)^3} =8$

Rewrite the equation as:

$(x-2)^{\frac{3}{4}}=8\\ \\(x-2)^{\frac{3}{4}}=2^3$

Hence,

$\left((x-2)^{\frac{3}{4}}\right)^{\frac{4}{3}}=(2^3)^{\frac{4}{3}}\\ \\x-2=2^{3\cdot \frac{4}{3}}\\ \\x-2=2^4\\ \\x-2=16\\ \\x-2+2=16+2\\ \\x=18$

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3 years ago

At the dog park, 2 dogs are black with spots, 5 dogs are white with spots, 1 dog is solid white, and 4 dogs are solid black. Wha

Nikolay [14]

Its 11/12 , you need to divide the "wanted results" (every dog which is either black, with spots or both ) by every every possible result ( all dogs ). so 11/12=0.92

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3 years ago

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