If a rink is 3 times its width and the width is 10m what is the area

Marcus drew a line from point Y to point W in the rectangle shown below. He created two identical triangles. Classfy the triangl

VikaD [51]

The triangles that would be created if the rectangle has a length and width that are different is a right scalene triangle.

It will have one right angle and all three sides of the triangle will be different lengths because the hypotenuse (the diagonal will be longer than the other two sides.

6 0

3 years ago

Marley had $495.66 in her bank account after she paid her monthly bills. She took her sister out to lunch, and paid $38.90. How

SOVA2 [1]

Answer: the answer is $456.76

Step-by-step explanation: All you have to do is subtract 38.90 from 495.66 and get your answer

5 0

2 years ago

Use your understanding of the unit circle and trigonometric functions to find the values requested.

vfiekz [6]

Answer:

a) For this case we can use the fact that $sin (\pi/3) = \frac{\sqrt{3}}{2}$

And for this case since we ar einterested on $-\frac{\pi}{3}$ and we know that the if we are below the y axis the sine would be negative then:

$sin (-\pi/3) = -\frac{\sqrt{3}}{2}$

b) From definition we can use the fact that $tan x= \frac{sin x}{cos x}$ and we got this:

$tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}$

We can use the notabl angle $\pi/4$ and we know that :

$sin (\pi/4) = cos(\pi/4) = \frac{\sqrt{2}}{2}$

Then we know that $5\pi/4$ correspond to 225 degrees and that correspond to the III quadrant, and we know that the sine and cosine are negative on this quadrant. So then we have this:

$tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}= \frac{\frac{sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1$

Step-by-step explanation:

For this case we can use the notable angls given on the picture attached.

Part a

For this case we can use the fact that $sin (\pi/3) = \frac{\sqrt{3}}{2}$

And for this case since we ar einterested on $-\frac{\pi}{3}$ and we know that the if we are below the y axis the sine would be negative then:

$sin (-\pi/3) = -\frac{\sqrt{3}}{2}$

Part b

From definition we can use the fact that $tan x= \frac{sin x}{cos x}$ and we got this:

$tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}$

We can use the notabl angle $\pi/4$ and we know that :

$sin (\pi/4) = cos(\pi/4) = \frac{\sqrt{2}}{2}$

Then we know that $5\pi/4$ correspond to 225 degrees and that correspond to the III quadrant, and we know that the sine and cosine are negative on this quadrant. So then we have this:

$tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}= \frac{\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1$

6 0

3 years ago

Graph y= 2/3x-4<br><br> How do I graph this?

umka21 [38]

Answer:

Read below !!

Step-by-step explanation:

Since you are already given the full equation, you would just follow the steps of plotting a line! I start usually by plotting the y-intercept, which is always on the y-axis. In this case, that would be -4 ! You mark -4 on the line, and from there, you would use RISE/RUN to find out the slope of the line. Since it's 2/3, you would rise 2, and go to the right 3, all from the point -4. You should do that about two times in order to get your line !!

I hope this helps !!

6 0

2 years ago

Triangles F G H and F J H share common side F H. Sides F G and G H are congruent. Sides F J and J H are congruent.

OlgaM077 [116]

ΔFGH is congruent to ΔFJH They are not congruent because only one pair of corresponding sides is congruent.

The correct option is (C)

<h3></h3><h3>What is Congruency?</h3>

Two geometric figures are said to be congruent, or to be in the relation of congruence, if it is possible to superpose one of them on the other so that they coincide throughout.

Given:

ΔFGH and ΔFJH share common side FH. Sides FG and GH are congruent.

As, per the information, it can be seen that the triangles are not congruent as one pair of corresponding side is not congruent.

Learn more about congruency here:

brainly.com/question/7888063

#SPJ1

3 0

2 years ago