If the triangle is a right triangle, then
(3x)² + x² = (10)² .
9x² + x² = 100
10x² = 100
x² = 10
x = √10 = approx. 3.1622...
If ' x ' is <em>anything less than √10</em> , then the short sides are too short
to make a right angle at the top, and the angle where they meet
is obtuse.
' x ' has to be greater than 2.5 ... otherwise the two short sides
can't stretch far enough to reach both ends of the long side (10) .
So, if 2.5 < x < √10 , then there is a triangle, and it's obtuse.
Substitution
-2x+8=x^2-9x+18
x^2-7x+10=0
Factoring, we get
(x-5)(x-2)=0
x=5, x=2
If x equals 5,
y=-2(5)+8=
-10+8=
-2
Therefore, we derive our first solution:
<h2><u><em>
x=5,</em></u></h2><h2><u><em>
y=-2</em></u></h2>
Now we solve for our second x
If x=2,
y=-4+8=
4
Therefore, we derive our second solution:
<h2><u><em>
x=2</em></u></h2><h2><u><em>
y=4</em></u></h2>
<u><em></em></u>
-Hunter
X + 7 < 2x +7
therefore
<span>x < 2x
</span>x > 0
another:
25 + 7 > 10 + 7
therefore
25 > 10
Answer:
Step-by-step explanation:
The quadrilateral has 4 sides and only two of them are equal.
A) to find PR, we will consider the triangle, PRQ.
Using cosine rule
a^2 = b^2 + c^2 - 2abcos A
We are looking for PR
PR^2 = 8^2 + 7^2 - 2 ×8 × 7Cos70
PR^2 = 64 + 49 - 112 × 0.3420
PR^2 = 113 - 38.304 = 74.696
PR = √74.696 = 8.64
B) to find the perimeter of PQRS, we will consider the triangle, RSP. It is an isosceles triangle. Therefore, two sides and two base angles are equal. To determine the length of SP,
We will use the sine rule because only one side,PR is known
For sine rule,
a/sinA = b/sinB
SP/ sin 35 = 8.64/sin110
Cross multiplying
SPsin110 = 8.64sin35
SP = 8.64sin35/sin110
SP = (8.64 × 0.5736)/0.9397
SP = 5.27
SR = SP = 5.27
The perimeter of the quadrilateral PQRS is the sum of the sides. The perimeter = 8 + 7 + 5.27 + 5.27 = 25.54 cm
