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Vladimir79 [104]
4 years ago
15

Rearrange the forumla v = u + at for t.

Mathematics
2 answers:
bezimeni [28]4 years ago
7 0
T=v-u/a Hope this helps??!?
dedylja [7]4 years ago
7 0
Subtract u from both sides so you have v-u=at then divide both sides by a and you will have v-u all divided by a is equal to t
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A video rental company offers a plan that includes a membership fee of $5 and charges $1 for every DVD borrowed. They also offer
WINSTONCH [101]

Answer:

for $5 plan if he rents 47 dvd it will pay 47% as one DVS cost 1 $ .

Step-by-step explanation:

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2 years ago
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Which is the answer of the following question
fgiga [73]

Answer:

<u>B) 25.12 cm</u>

Step-by-step explanation:

<u>Arc length</u>

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2 years ago
Write √1694 in simplest form.<br> Please help.
belka [17]
√1694 = √121*14 = 11<span>√14

The simplest form of </span>√1694 is 11<span>√14. First, you need to find the highest number which can have a square root, and for 1694, that is 121. </span>
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3 years ago
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Round 789,091 to nearest ten thousand
irakobra [83]

790,000

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7 0
4 years ago
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Match the y-coordinate with the given x-coordinate for the equation y = log10x.
Andrew [12]

The non-algebraic functions are called transcendental functions. This include the logarithmic function. The definition of Logarithmic Function with Base a is as follows:


For \ x\ \textgreater \ 0, \ a \ \textgreater \ 0, \ and \ a \neq 1 \\ \\ y=log_{a}x \ if \ and \ only \ if \ x=a^{y} \\ \\ Then: \\ \\ f(x)=log_{a}x \\ \\ is \ called \ the \ logarithmic \ function \ with \ base \ a.


We know that the equations is:


y=log(10x)


So let's solve each case:


Case 1


x=\frac{1}{100} \\ \\ y=log(10(\frac{1}{100})) \\ \\ \therefore y=log(\frac{1}{10}) \\ \\ \therefore y=-1 \\ \\ So: \\ \\ \boxed{\ x=\frac{1}{100}} \ matches \ to \ \boxed{y=-1}


Case 2


x=\frac{1}{10} \\ \\ y=log(10(\frac{1}{10})) \\ \\ \therefore y=log(1) \\ \\ \therefore y=0 \\ \\ So: \\ \\ \boxed{\ x=\frac{1}{10}} \ matches \ to \ \boxed{y=0}


Case 3


x=1 \\ \\ y=log(10(1)) \\ \\ \therefore y=log(10) \\ \\ \therefore y=1 \\ \\ So: \\ \\ \boxed{\ x=1} \ matches \ to \ \boxed{y=1}


Case 4


x=10 \\ \\ y=log(10(10)) \\ \\ \therefore y=log(100) \\ \\ \therefore y=2 \\ \\ So: \\ \\ \boxed{\ x=10} \ matches \ to \ \boxed{y=2}


Case 5


x=100 \\ \\ y=log(10(100)) \\ \\ \therefore y=log(1000) \\ \\ \therefore y=3 \\ \\ So: \\ \\ \boxed{x=100} \ matches \ to \ \boxed{y=3}

5 0
4 years ago
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