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Svet_ta [14]
3 years ago
15

Consider function f.

Mathematics
1 answer:
tekilochka [14]3 years ago
7 0

Given:

The function is:

f(x)=\sqrt{7x-21}

To find:

The steps of finding the inverse function f^{-1}(x).

Solution:

We have,

f(x)=\sqrt{7x-21}

The steps of finding the inverse function are:

Step 1: Substitute f(x)=y.

y=\sqrt{7x-21}

Step 2: Interchange x and y.

x=\sqrt{7y-21}

Step 3: Taking square on both sides, we get

x^2=7y-21

Step 4: Adding 21 on both sides, we get

x^2+21=7y

Step 5: Divide both sides by 7.

\dfrac{1}{7}x^2+3=y

Step 6: Substitute y=f^{-1}(x).

\dfrac{1}{7}x^2+3=f^{-1}(x), where x\geq 0.

Therefore, the inverse of the given function is f^{-1}(x)=\dfrac{1}{7}x^2+3 and the arrangement of steps is shown above.

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Neporo4naja [7]

Answer:

The coordinates of the turning point are (2, -9)

Step-by-step explanation:

The coordinates of the turning points of the quadratic equation

y = ax² + bx + c, are (h, k), where

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∵ The equation of the curve is y = x² + bx + c

→ By comparing it with the form above

∴ a = 1

∵ The point (0, -5) lies on the curve

→ Substitute x by 0 and y by -5 in the equation to find the value f c

∵ -5 = (0)² + b(0) + c

∴ -5 = 0 + 0 + c

∴ -5 = c

→ Substitute it in the equatin

∴ y = x² + bx - 5

∵ The point (5, 0) lies on the curve

→ Substitute x by 5 and y by 0 in the equation to find the value f c

∵ 0 = (5)² + b(5) - 5

∴ 0 = 25 + 5b - 5

→ Add the like terms in the right side

∴ 0 = 20 + 5b

→ Subtract 5b from bth sides

∵ 0 - 5b = 20 + 5b - 5b

∴ -5b = 20

→ Divide both sides by -5 to find b

∴ b = -4

→ Substitute it in the equatin

∴ y = x² - 4x - 5

∵ a = 1 and b = -4

→ Substitute them in the rule of h above t find it

∵ h = \frac{-(-4)}{2(1)} = \frac{4}{2}

∴ h = 2

→ To find k, substitute x by 2 and y by k

∵ k = (2)² - 4(2) - 5

∴ k = 4 - 8 - 5

∴ k = -9

∴ The cordinates of the turning point are (2, -9)

6 0
2 years ago
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Semenov [28]

Answer:

(-2, -3)

(3, 12)

Step-by-step explanation:

To solve this, we're gonna get rid of the y's with substitution

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Let's make this equation equal to zero

Subtract 3 from both sides

x² + 2x - 3 = 3x + 3

            - 3         - 3

x² + 2x - 6 = 3x

Subtract 3x from both sides

x² + 2x - 6 = 3x

    - 3x        - 3x

x² - x - 6 = 0

Factor the equation

(x - 3)(x + 2) = 0

This means x can be -2 or 3

Let's solve it with -2 first, plug the new x in y = 3x + 3

y = 3(-2) + 3

y = -6 + 3 = -3

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y = 3(3) + 3

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Answer:

The radius of the circle r=12.

The area of a circle is 144π.

Step-by-step explanation:

The radius of the circle is r where 2πr=24π, r=12.

The area of a circle with radius 12 is

A=πr², A=π12², A=144π.

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