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Nitella [24]
3 years ago
5

What the square area with side length of 3/5 units

Mathematics
1 answer:
ElenaW [278]3 years ago
5 0

Answer:

9/25 units^2

Step-by-step explanation:

AREA(Square) = side * side = 3/5 *3/5 = 9/25 square units

Answer: 9/25 units ^2 :)

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CAN SOMEONE HELP PLEASE!!
grandymaker [24]
The predicted time remaining has decreased by 30 years, so the second one would be the answer
3 0
3 years ago
Complete the table of values for the equation, 16x + 4y = 12.
Ann [662]

The x-y coordinates for the given equation are: (-2,11),(-1,7),(0,3), (1,-1) and (2,-5).

<h3>Linear Function</h3>

A linear function can be represented by a line. The standard form for this equation is: ax+b , for example, y=2x+7. Where:

  • a= the slope;
  • b=the constant term that represents the y-intercept.

The given equation is 16x + 4y = 12. For solving this question, you should replace the given values of x  for finding the values of y.

Thus,

  • For x= -2,  the value of y will be:

       16*(-2)+4y=12

      -32+4y=12

      4y=12+32

     4y=44

      y=11

  • For x= -1,  the value of y will be:

         16*(-1)+4y=12

  • -16+4y=12
  • 4y=12+16
  • 4y=28
  • y=7
  • For x= 0,  the value of y will be:

         16*(0)+4y=12

  • 0+4y=12
  • 4y=12
  • 4y=12
  • y=3
  • For x= 1,  the value of y will be:

         16*(1)+4y=12

  • 16+4y=12
  • 4y=12-16
  • 4y=-4
  • y= -1
  • For x= 2,  the value of y will be:

         16*(2)+4y=12

  • 32+4y=12
  • 4y=12-32
  • 4y=-20
  • y= -5

Read more about the linear equation here:

brainly.com/question/1884491

#SPJ1

7 0
2 years ago
Pratap puri rowed 10 miles down a river in 2 ​hours, but the return trip took him 2 and one half hours. Find the rate pratap can
N76 [4]

Answer:

<em>Rate of Pratap in still water is 4.5 miles/hour and rate of current is 0.5 miles/hour.</em>

Step-by-step explanation:

Pratap Puri rowed 10 miles down a river in 2 ​hours, but the return trip took him 2.5 hours.

We know that, Speed = \frac{Distance}{Time}

So, the <u>speed of Pratap with the current</u> will be:  (\frac{10}{2})miles/hour = 5 miles/hour

and the <u>speed of Pratap against the current</u> will be:  (\frac{10}{2.5})miles/hour = 4 miles/hour.

Suppose, the rate of Pratap in still water is x and the rate of current is y.

So, the equations will be........

x+y= 5 .............................. (1)\\ \\ x-y=4 .............................. (2)

Adding equation (1) and (2) , we will get......

2x=9\\ \\ x=\frac{9}{2}= 4.5

Now, plugging this x=4.5 into equation (1), we will get.....

4.5+y=5\\ \\ y=5-4.5 =0.5

Thus, Pratap can row at 4.5 miles per hour in still water and the rate of the current is 0.5 miles/hour.

6 0
4 years ago
The temperature is 45°F. The temperature will decrease by 2°F each hour. Let h be the number of hours.
Varvara68 [4.7K]
45 - 2t < 32 ( where t is time and you can replace it with x or h if you prefer)
Solving for t you get:
45 - 2t - 32 < 0
45 - 32 < 2t
13 < 2t
13/2 < t
Or the temperature will drop below 32F after 6 and a half hours
8 0
3 years ago
Help please I neeed help
Whitepunk [10]

Answer:

D

Step-by-step explanation:

f(x) would be -2x + 3 because the y-intercept is 3 and the slope is -2.

Slope: (3 - 1)/(0 - 1) = -2

The slope of g(x) is -7.

-2 > -7

5 0
3 years ago
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