An observer (0) spots a plane flying a 35° angle to his horizontal line of the sight. If the plane is flying at an altitude of 1
7,000 ft, what is the distance (x) from the plane (P) to the observer (O)?
1 answer:
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Answer:
Step-by-step explanation:
We want to find the distance between two points, so the following formula is used.
Where (x₁, y₁) and (x₂, y₂) are the points we are finding the distance between.
We are given the points (-2, -1) and (3,2). If we match the corresponding value and variable we see that:
- x₁= -2
- y₁= -1
- x₂= 3
- y₂= 2
Substitute the values into the formula.
Solve the parentheses.
- -2 -3 = -5
- 2--1 = 2+ 1 = 3
Solve the exponents.
- (-5)²= -5*-5= 25
- (3)²= 3*3=9
Add.
This radical cannot be simplified, so the distance between the two points is <u>√34</u> and <u>choice 3 </u> is correct.