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gladu [14]
3 years ago
15

I will NAME YOU THE BRAINIEST

Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
8 0

Answer:

see below

Step-by-step explanation:

Since the quadrilateral is inscribed in the circle, the opposite angles add to 180.

<V+ <B = 180

74+ <B = 180

Subtract 74 from each side

74-74+ <B = 180-74

<B = 106

We now need to find arc AB

Arc AC is 2* <V = 2*74 =154

We know arc AC = arc AB + arc BC

                 154 = arc AB + 86

Subtract 86 from each side

                154-86 = arc AB + 86 -86

                  68 = arc AB

Aleonysh [2.5K]3 years ago
5 0

Answer:

Arc AB = 62°

Angle B = 106°

Step-by-step explanation:

Angle V + Angle B = 180

(Opposite angles add up to 180)

74 + Angle B = 180

Angle B = 106°

Let O be the centre of the circle.

Angle OBC = (180-86)/2 = 47°

Angle BOA = 106 - 47

= 59° = Angle AOB

Angle Arc AB = 180 - 2(59) = 62°

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The sum of two numbers is 70 and their difference is 30. Find the two numbers
ikadub [295]

Answer:

Our two numbers are 50 and 20

Step-by-step explanation:

Sum means add together

Difference means subtract each other

x + y = 70

x - y = 30

subtract from each other

2x = 100

divide both sides by 2

x = 50

our first number is 50

50 + y = 70

subtract both sides by 50

y = 20

Our two numbers are 50 and 20

8 0
3 years ago
Solve each equation with the quadratic formula.<br> x2 -7x +10= 0
zhenek [66]

Answer: x=5, x=2

Step-by-step explanation: try symbolab for these questions...it helps out a lot.

5 0
2 years ago
Pro
Firdavs [7]

Answer:

C. Both (1, 11) and (-1, -5)

Step-by-step explanation:

The missing options are:

<em> A. Only (1, 11) </em>

<em>B. Only (-1, -5)  </em>

<em>C. Both (1, 11) and (-1, -5) </em>

<em>D. Neither </em>

To check if an ordered pair is a solution of an equation, replace one variable into the equation an calculate the other one.

Replacing x = 1, we get:

y = 8(1) + 3

y = 11

then (1, 11) is a solution

Replacing x = -1, we get:

y = 8(-1) + 3

y = -5

then (-1, -5) is a solution

8 0
3 years ago
I NEED HELP PLEASE, THANKS! :)
Aleonysh [2.5K]

but where is ur question ??????

5 0
2 years ago
Read 2 more answers
Find four geometric means between 25 and 800.
SVEN [57.7K]

Actually, you have to find four missed terms of geometrical sequence. Denote

a_1=25,\\ a_6=800

and r - ratio, then

a_2=a_1\cdot r=25r,\\a_3=a_1\cdot r^2=25r^2,\\a_4=a_1\cdot r^3=25r^3,\\a_5=a_1\cdot r^4=25r^4,\\a_6=a_1\cdot r^5=25r^5.

Since a_6=800, you have that 800=25r^5, then

r^5=\dfrac{800}{25} =32,\\r=2.

Now substitude r=2 in each of unknown 4 terms:

a_2=25\cdot 2=50,\\a_3=25\cdot 2^2=100,\\a_4=25\cdot 2^3=200,\\a_5=25\cdot 2^4=400.

Answer: four geometric means between 25 and 800 are 50, 100, 200, 400.

8 0
3 years ago
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