NEED HELP ASAP!! Please solve- Solve 3x2 + 6x + 6 = 0.

Triangle sum theorem WILL MARK BRAINLIEST

sergiy2304 [10]

Answer:

So for a hint to help you...when you are looking at a triangle on a 180 degree line, each angle adds up to 180 degrees. So for example, on #9 on the top of the triangle, one of the angles is 49 degrees so you want to subtract that from 180 ( 180 - 49 = X ) ( X = angle 1 and 2 ) so angle 1 and 2 added together equals X. In this case, ( X = 131 degrees ) Every triangle equals 180 degrees too. So since this angle has 3 different angles on the line, you can do the rest of the problems and come back to these because you can subtract angle 4 and 73 to get angle 2.

(still on #9) Angle 3, as you can see only has one other number beside it (73) so it makes this one very easy. ( 180 - 73 = X ) ( X = 107 ) Angle 3 = 107 degrees

Angle 5. Subtract the 49 above angle 5 from 180 and the result will be angle 5. ( 180 - 49 = X ) ( X = Angle 5 ) X/angle 5 = 131.

Now you can get angle 4, which gives you angle 2 and 1. ( 180 - 131 = Angle 4 ) (Angle 4 = 49)

Angle 2. In the triangle, we have 73 degrees, and 49 degrees. So the equation for this one is, ( 180 - 73 - 49 = Angle 2 ) ( Angle 2 = 58 )

Angle 1. On this line, we have 49 degrees and 2=58 degrees. ( 180 - 58 - 49 = Angle 1 ) ( Angle 1 = 73 )

Lastly, Angle 3. The side of this triangle will also equal 180, just like the top line. Angle 1 = 73 degrees so as you now know, subtract that from 180 and get angle 3. ( 180 - 73 = Angle 3 ) (Angle 3 = 107 )

1: 73 degrees

2: 58 degrees

3: 107 degrees

4: 49 degrees

5: 131 degrees

I know this is a lot to read, but I really hope I explained it to where you can understand it now.

8 0

3 years ago

an equilateral triangle is shown inside a square inside a regular pentagon inside a regular hexagon. write an expression for the

Alex73 [517]

We know that
the area of the shaded regions is equal to
area of the shaded region 1+area of the shaded region 2

step 1
find the area of the shaded region 1
area of the shaded region 1=Area regular Hexagon-Area regular Pentagon

step 2
find the area of the shaded region 2
area of the shaded region 2=Area of a square-Area of the equilateral triangle

therefore
the area of the shaded regions is equal to
[Area regular Hexagon-Area regular Pentagon]+[Area of a square-Area of the equilateral triangle]

7 0

3 years ago

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At a charity fund-raiser, adult tickets were sold for $10 each and children's tickets were sold for $4 each. Write an algebra

love history [14]

Answer:

the all adult tickets made out 2440$

the all children tickets made out 1548

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3 years ago

McKenna is volunteering in the media center at school. She has 125 books that need to go on the shelves. Each shelf holds 25 boo

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