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andrey2020 [161]
2 years ago
5

Can someone please help me?

Mathematics
1 answer:
shepuryov [24]2 years ago
4 0

Answer:

24

Step-by-step explanation:

area = wl (6×4 = 24)

w width l length

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An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
3 years ago
suppose 60% of kids who visit a doctor have a fever, and 20% of kids with a fever have sore throats. what's the probability that
kkurt [141]

Answer:

0.12

Step-by-step explanation:

Suppose there are 100 kids

60% have fever, so <em><u>what is 60% of 100?</u></em>

We convert percentage to decimal and multiply:

60/100 = 0.6

0.6 * 100 = 60 have fever

20% of the people having fever (60 of them) have sore throats, so,

<u><em>What is 20% of 60?</em></u>

We convert percentage to decimal and multiply:

20/100 = 0.2

0.2 * 60 = 12 have sore throat

So, how many people are there with fever AND sore throat, that is 12. We took initially there to be 100 people. Hence, the probability is:

\frac{12}{100}=0.12

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Sever21 [200]

Answer:

so sorry !  but i need it

Step-by-step explanation:

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