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Inessa05 [86]
3 years ago
10

PLEASE HELP with math

Mathematics
1 answer:
MArishka [77]3 years ago
6 0

Answer:

1. 4 * 7 * 11 = 308

2. 7 * 7 * 4/2 = 98

3. 98 + 308 = 406

Hope this helps!

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Simplify 3[2^3 + (4-2)^3 - (6-2)^2]
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\boxed{0}

.

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3(2^3 + (4 - 2)^3 - (6 - 2)^2)

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Salaries for various positions can vary significantly depending on whether the company is in the public or private sector. The U
DIA [1.3K]

Answer:

a) 0.004

b) 0.9609                                                

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 76503

Standard Deviation, σ = 8850

We are given that the distribution of annual salaries is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(salary greater than 100,000)

P(x > 100000)

P( x > 100000) = P( z > \displaystyle\frac{100000 - 76503}{8850}) = P(z > 2.655)

= 1 - P(z \leq 2.655)

Calculation the value from standard normal z table, we have,  

P(x > 100000) = 1 - 0.996 = 0.004  = 0.4\%

b) P(sample mean annual salary falls between 70,000 and 80,000 dollars)

Sample size, n = 20

Standard error due to sampling =

\dfrac{\sigma}{\sqrt{n}} = \dfrac{8850}{\sqrt{20}} = 1978.92

P(70000 \leq x \leq 80000) = P(\displaystyle\frac{70000 - 76503}{1978.92} \leq z \leq \displaystyle\frac{80000-76503}{1978.92})\\\\ = P(-3.286 \leq z \leq 1.767)\\\\= P(z \leq 1.767) - P(z < -3.286)\\=0.9614 - 0.0005= 0.9609 = 96.09\%

P(70000 \leq x \leq 80000) = 96.09\%

7 0
3 years ago
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