All categories

3 years ago

PLEASE HELP with math

Mathematics

1 answer:

MArishka [77]3 years ago

6 0

Answer:

1. 4 * 7 * 11 = 308

2. 7 * 7 * 4/2 = 98

3. 98 + 308 = 406

Hope this helps!

You might be interested in

Mr. Price earns $350 per week working in an appliance store. In addition, he earns 3% commission on all of his sales. Last week,

fgiga [73]

C $464 as he earned $350 plus $114 commission

6 0

3 years ago

Need help,with the step, equation pleases help really don’t understand

kap26 [50]

Use Socratic it gives u a step by step explanation

4 0

3 years ago

Simplify 3[2^3 + (4-2)^3 - (6-2)^2]

Ivahew [28]

Answer:

$\boxed{0}$

Step-by-step explanation:

$3(2^3 + (4 - 2)^3 - (6 - 2)^2)$

$= 3(2^3 + 2^3 - 4^2)$

$= 3(2.2^3 - (2^2)^2)$

$= 3(2^4 - 2^4)$

$= 3(0)$

$= 0$

6 0

3 years ago

Find the whole 25% of is 21

Nat2105 [25]

25% of 84 is 21

21 divided by 25%=84

5 0

3 years ago

Read 2 more answers

Salaries for various positions can vary significantly depending on whether the company is in the public or private sector. The U

DIA [1.3K]

Answer:

a) 0.004

b) 0.9609

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 76503

Standard Deviation, σ = 8850

We are given that the distribution of annual salaries is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(salary greater than 100,000)

P(x > 100000)

$P( x > 100000) = P( z > \displaystyle\frac{100000 - 76503}{8850}) = P(z > 2.655)$

$= 1 - P(z \leq 2.655)$

Calculation the value from standard normal z table, we have,

$P(x > 100000) = 1 - 0.996 = 0.004 = 0.4\%$

b) P(sample mean annual salary falls between 70,000 and 80,000 dollars)

Sample size, n = 20

Standard error due to sampling =

$\dfrac{\sigma}{\sqrt{n}} = \dfrac{8850}{\sqrt{20}} = 1978.92$

$P(70000 \leq x \leq 80000) = P(\displaystyle\frac{70000 - 76503}{1978.92} \leq z \leq \displaystyle\frac{80000-76503}{1978.92})\\\\ = P(-3.286 \leq z \leq 1.767)\\\\= P(z \leq 1.767) - P(z < -3.286)\\=0.9614 - 0.0005= 0.9609 = 96.09\%$

$P(70000 \leq x \leq 80000) = 96.09\%$

7 0

3 years ago