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GrogVix [38]
3 years ago
10

Please explain how to simplify for g(x) f(x) = 2x + 4 g(x) = f(x + 7)-5

Mathematics
2 answers:
yuradex [85]3 years ago
5 0

Answer:

Step-by-step explanation:

yulyashka [42]3 years ago
3 0

Answer:

ytea

Step-by-step explanation:

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Can someone please help me find the range
defon

Answer:

Step-by-step explanation

4 0
3 years ago
Please help me ASAP easy problem giving brainlist!!
never [62]

Answer:

x ≥ 1

Step-by-step explanation:

Since it's a closed circle x could also be equal to 1. Also, since the arrow is pointing away from 1 the answer of x is greater than 1, therefore the answer is x ≥ 1.

8 0
3 years ago
Find the remaining trigonometric ratios of θ if csc(θ) = -6 and cos(θ) is positive
VikaD [51]
Now, the cosecant of θ is -6, or namely -6/1.

however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.

we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

\bf csc(\theta)=-6\implies csc(\theta)=\cfrac{\stackrel{hypotenuse}{6}}{\stackrel{opposite}{-1}}\impliedby \textit{let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\pm\sqrt{6^2-(-1)^2}=a\implies \pm\sqrt{35}=a\implies \stackrel{IV~quadrant}{+\sqrt{35}=a}

recall that 

\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad\qquad 
cos(\theta)=\cfrac{adjacent}{hypotenuse}
\\\\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{adjacent}{opposite}
\\\\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
\qquad \qquad 
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}

therefore, let's just plug that on the remaining ones,

\bf sin(\theta)=\cfrac{-1}{6}
\qquad\qquad 
cos(\theta)=\cfrac{\sqrt{35}}{6}
\\\\\\
% tangent
tan(\theta)=\cfrac{-1}{\sqrt{35}}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{\sqrt{35}}{1}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}

now, let's rationalize the denominator on tangent and secant,

\bf tan(\theta)=\cfrac{-1}{\sqrt{35}}\implies \cfrac{-1}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{-\sqrt{35}}{(\sqrt{35})^2}\implies -\cfrac{\sqrt{35}}{35}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}\implies \cfrac{6}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{6\sqrt{35}}{(\sqrt{35})^2}\implies \cfrac{6\sqrt{35}}{35}
3 0
3 years ago
If f(x) = 0.8(2 – x), what is the value of f(–2)?
Sergio039 [100]
With functions, you take the number that is in the ( ), so we have f(-2), and take the fomula f(x) = 0.8(2 – x) and everywhere you see an 'x' replace it with the -2 f(–2)=0.8(2 – (-2)) 

We will have to work with the expression of 0.8(2-(-2) When you want to evaluate these types of expressions, you want to use the Order of Operations: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction. First we have to evaluate the parentheses. What is 2-(-2)
 its 4.

ok now you got 0.8 (4)

 Now we have the remains of 0.8(4). If a number is within the parenthesis, then it means that we have to multiply the number inside with the number that is outside. What is 0.8*4 its 3.2 soooo your answer is going to be

3.2
5 0
3 years ago
Use the distribute property to find two expressions that are equivalent to 7(3x-4)
timama [110]

84 Is the answer thank me later god bless you

8 0
3 years ago
Read 2 more answers
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