Answer:
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Step-by-step explanation:
PLEASE!
<h3>
Answer: x*a^2 or a^2*x</h3>
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Work Shown:
a^(b+2) = a^b*a^2 ... break up the exponent
a^(b+2) = x*a^2 ... replace a^b with x
We don't know the value of 'a' nor the value of x, so we cannot evaluate further. This is the same as a^2*x because order of multiplication does not matter. For example, 2*3 = 6 and 3*2 = 6, so 2*3 = 3*2.
The answer is the square root of 18 because of Pythagorean theorem
Answer: option 2 describes best
Step-by-step explanation:Given Marisol grouped the terms and factored the GCF out of the groups of the polynomial 6x3 – 22x2 – 9x + 33. Her work is shown.
Step 1: (6x3 – 22x2) – (9x + 33)
Step 2: 2x2(3x – 11) – 3(3x + 11)
Marisol noticed that she does not have a common factor. Which accurately describes what Marisol should do next?
Marisol should realize that her work shows that the polynomial is prime.
Marisol should go back and group the terms in Step 1 as (6x3 – 22x2) – (9x – 33).
Marisol should go back and group the terms in Step 1 as (6x3 – 22x2) + (9x – 33).
Marisol should refactor the expression in Step 2 as 2x2(3x + 11) – 3(3x + 11).
According to question Marisol grouped the terms and has done factorisation of the given polynomial 6x^3 – 22x^2 – 9x + 33.
In step 1 she has written as (6x^3 – 22x^2) – (9x + 33)
Marisol has to go to step 1 in order to correct her mistake. She has to group the expression as (6x^3 – 22x^2) – (9x – 33) so that she will be able to get the expression as
6x^3 – 22x^2 – 9x + 33 after opening the brackets.