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aleksklad [387]
4 years ago
9

Two video rental clubs offer two different rental fee plans.Club A charges $12 for membership and $2 for each rented video.Club

B charges $4 for membership fee and charges $4 for each rented video.Which video rental club is the better deal and why?
Mathematics
1 answer:
notka56 [123]4 years ago
3 0

Answer: Club A

 

EXPLANATION

Given,

Club A charges $12 for membership and $2 for each rented video.

The deal in Club A can be represented by the function, f(x) = 12 + 2x

 

Club B charges $4 for membership fee and charges $4 for each rented video.

The deal in Club B can be represented by the function, f(x) = 4 + 4x

 

 

To determine which video rental club is the better deal

First, we find the number of videos where the amount spent will be the same

 

That is, when 4 + 4x = 12 + 2x

 

Subtract 4 from both sides of the equation

4 + 4x – 4 = 12 + 2x – 4

4x = 8 + 2x

 

Subtract 2x from both sides of the equation

4x – 2x = 8 + 2x – 2x

2x = 8

 

Divide both sides by 2

2x/2 = 8/2

x = 4

 

Since the deals for club B and club B will be of equal expense by the time a total of 4 videos have been rented, the better deal is the one that is cheaper when more than 4 videos have been rented.

 

Take a random value of x that is greater than 4, say 6

 

For the deal in Club A, f(x) = 12 + 2x

= 12 + 2(6)

= 12 + 12

= $24

 

For the deal in Club A, f(x) = 4 + 4x

= 4 + 4(6)

= 4 + 24

= $28

 

Since the deal in Club A is cheaper on the long run (i.e for 5 videos and above), it is a better deal than that of Club B

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Coach Evans recorded the height, in inches of each player on his team. The results are shown.
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61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile (Q_1)

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile (Q_3)

Terms in arranged in ascending order:

57,60,60,61,62,62,63,63,64

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

Q_1 is median of terms 57,60,60,61

Number of terms (n) = 4

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60

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So, 25% of the heights of a team is less than 60 inches

Q_3 is the median of terms 62,63,63,64

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63

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So, 75% of the heights of a team is less than 63 inches

Interquartile range = Q_3-Q_1=63-60=3

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

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