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I used MathPapa to get the answer </span>
Answer:
x = 12
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
Step-by-step explanation:
<u>Step 1: Define equation</u>
-2(x - 4) = -16
<u>Step 2: Solve for </u><em><u>x</u></em>
- Distribute -2: -2x + 8 = -16
- Isolate <em>x</em> term: -2x = -24
- Isolate <em>x</em>: x = 12
<u>Step 3: Check</u>
<em>Plug in x to verify it's a solution.</em>
- Substitute: -2(12 - 4) = -16
- Subtract: -2(8) = -16
- Multiply: -16 = -16
Here we see that -16 does indeed equal -16.
∴ x = 12 is a solution of the equation.
ax² + bx + c = 0
x = (-b ± √(b² - 4ac))/2a
First, rewrite the first equation so that the first coefficient is 1. Divide everything by a.
(ax² + bx + c = 0)/a =
x² + (b/a)x + (c/a) = 0
Isolate (c/a) by subtracting (c/a) from both sides
x² + (b/a)x + (c/a) (-(c/a) = 0 (- (c/a)
x² + (b/a)x = 0 - (c/a)
Add spaces
x² + (b/a)x = -c/a
Take 1/2 of the middle term's coefficient and square it. Remember that what you add to one side, you add to the other.
x² + (b/a)x + (b/2a)² = -c/a + (b/2a)²
Simplify the left side of the equation.
x² + (b/a)x + (b/2a)² = (x + (b/2a))²
(x + b/2a))² = ((b²/4a²) - (4ac/4a²)) -> ((b² - 4ac)/(4a²))
Take the square root of both sides of the equation
√(x + b/2a))² = √((b²/4a²) - (4ac/4a²))
x + b/(2a) = (±√(b² - 4ac)/2a
Simplify. Isolate the x.
x = -(b/2a) ± (∛b² - 4ac)/2a = (-b ± √(b² - 4ac))/2a
~
Answer:
16
Step-by-step explanation:
Make a proportion:
66/12 = (104-r)/r
Simplify:
r = 16
