For this case we have the following function:
![f (x) = 3x + 5 ](https://tex.z-dn.net/?f=f%20%28x%29%20%3D%203x%20%2B%205%0A)
Rewriting the function we have:
![y = 3x + 5 ](https://tex.z-dn.net/?f=y%20%3D%203x%20%2B%205%0A)
From here, we must clear the value of x.
We have then:
![3x = y - 5 x = (y-5) / (3)](https://tex.z-dn.net/?f=3x%20%3D%20y%20-%205%0A%0Ax%20%3D%20%28y-5%29%20%2F%20%283%29)
We make the corresponding variable changes:
Answer:
The inverse of the function f (x) is given by:
Ok so Mr gals takes 7 hours and Mr Lee's takes 6.25 hours to mow and those added equal 13.25 so 63 divided by 4 equals 15.75 so if we take that and minus gal and Lee's lawn it takes 2.50 hours to mow Mr unknowns lawn
Answer:
![f(4) = 1.39](https://tex.z-dn.net/?f=f%284%29%20%3D%201.39)
Step-by-step explanation:
Given
![f(x) = ln\ x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20ln%5C%20x)
Required
Find f(4)
Substitute 4 for x in ![f(x) = ln\ x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20ln%5C%20x)
![f(4) = ln\ 4](https://tex.z-dn.net/?f=f%284%29%20%3D%20ln%5C%204)
![f(4) = 1.38629436112](https://tex.z-dn.net/?f=f%284%29%20%3D%201.38629436112)
Approximate:
![f(4) = 1.39](https://tex.z-dn.net/?f=f%284%29%20%3D%201.39)
Every function associates input values with output values. The domain of a function is the set of all the inputs the function accepts.
You will basically always find your function graphed with the inputs on the horizontal axis and the outputs on the vertical axis. This means that every point on the graph has coordinates
, and the domain is the set of all the x values.
The points on your red line have all coordinates
, where d starts from 0 and ranges up to 12. So, the domain of the function is ![[0,12]](https://tex.z-dn.net/?f=%20%5B0%2C12%5D%20)