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MrRa [10]
3 years ago
8

What is 9- negative 7?

Mathematics
1 answer:
Dafna1 [17]3 years ago
6 0

Nine subtracted from negative seven would be sixteen.


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The area of a rectangle is 48x®y7
Jlenok [28]

Answer:

D

Step-by-step explanation:

Remember, area equals width x height so you can set up this equation.

48x^8y^7=6x^2y^4 * w

Solving for w,

\frac{48x^8y^7}{6x^2y^4} =w

Simplifying,

8x^6y^3

Thus, D is the answer

7 0
3 years ago
On a vacation in Puerto Rico rose jumped off a cliff into a river in El Yunque go forest reserve her height as a function of tim
gayaneshka [121]

Answer: t = 6 s

Step-by-step explanation:

When Rose hit the water, the height of the jump is 0, so: h(t) = 0.

Resolving it, we have:

-16t² + 16t + 480 = 0

To simplify the second degree equation, divided it by 16:

-t² + t + 30 = 0

Now, solve the equation using Bhaskara:

Δ = 1² - 4. (-1) . 30

Δ = 1 + 120

Δ = 121

t = \frac{-1+\sqrt{121} }{-2}

t₁ = \frac{-1 + 11}{-2} = - 5

t₂ = \frac{-11-11}{-2} = 6

Since time can be negative, it took t = 6s for Rose to hit the water.

6 0
3 years ago
Simplify the algebraic expression by combining the like (or similar) terms -3+5y+9
USPshnik [31]

Answer:

5y+6

Step-by-step explanation:

-3 and 9 are like terms which can be simplified to 6.

7 0
3 years ago
Read 2 more answers
What are the domain and range of the function?
jekas [21]

Answer:

  see below

Step-by-step explanation:

The square root function produces a non-negative output for a non-negative input. When its output is negated, it produces a non-positive output for a non-negative input.

The input (domain) is from 0 to infinity: [0, ∞).

The output (range) is from negative infinity to zero: (-∞, 0].

____

A graph of the function is included for your convenience.

6 0
3 years ago
The fastest NASCAR qualifying speed is 313 feet per second. How many miles per hour is that?
Semmy [17]

Answer:

213.41 mph.

Step-by-step explanation:

Multiply by 3600 ( seconds in an hour) and divide by 5280 (feet in a mile).

= 213.41 mph.

3 0
3 years ago
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