<span>x^2 + y^2 – x – 2y – 11/4 = 0
x^2 - x + y^2 - 2y = 11/4
Using completing the square method:
x^2 - x + 1/4 + y^2 - 2y + 1 = 11/4 + 1 + 1/4
(x - 1/2)^2 + (y - 1)^2 = 4
coordinates: (1/2 , 1)
radius: sqrt (4)</span>
Hahah it’s funny how there was another one of these in my feed after I just answer on the other one. HAVE A NICE DAY :)
Answer:
81π for the x axis.
Step-by-step explanation:
STEP ONE: Determine the intersection.
we are given from the question that y = x^2 and y = 6x − x^2. Therefore if y = x^2, then we will have;
x^2 = 6x - x^2 ---------------------------------------------------------------------------------[1].
Solving and factorizing the equation [1] above give us x = 0 and x = 3 (that is x[6 -2x] = 0 ). Therefore, the point of intersection = (0,0) and (3,9).
<u>STEP TWO</u><em>: </em>Determine the value for the cross sectional area.
The cross sectional area= [6x - x^2]π - [x2]^2 π. --------------[2].
The cross sectional area = -12 π[x -3]x^2.
<u>STEP THREE:</u> integrate the cross sectional area taking x =3 and x =0 as the upper and lower integration limits or boundaries with respect to dx to determine the vome in the x axis.
<h3>volume =∫-12 π[x -3]x^2 dx.</h3><h3 /><h3>volume = -12 π[ (3)^4/4 - (3)^3 ] = 81π.</h3>
volume, v with respect to the x axis = 81π
Answer:
6/5m
or
1 1/5m
Step-by-step explanation:
5 - 3 4/5 = x
5/1 - 19/5 = x
5/1(5/5) - 19/5 = x
25/5 - 19/5 = x
25/5 - 19/5 = 6/5
x = 6/5 or 1 1/5
