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sweet-ann [11.9K]
4 years ago
13

Given the function f(x) = 8(x − 4) − 18, determine the value of x such that f(x) = 22

Mathematics
1 answer:
NNADVOKAT [17]4 years ago
5 0

Answer:

c. 9

Step-by-step explanation:

1. The starting equation to find f(22) is 22=8(x-4)-18

2. Next, distribute(multiply) the 8 to the x and -4 which would make the equation 22=8x-32-18

3. After that, combine the like terms (-32-18) which would give us 22=8x-50

4. Now, we can also combine the 22 and the -50 but they are on different sides of the equation. So, we have to move the -50 to the left side of the equation by adding 50 to both sides which would cancel -50 on the right side, thus "moving" it to the left side which would give us 72=8x

5. Lastly, we have to isolate x right? so to get rid of the 8, you divide both sides by 8 since 8 is multiplying with x which would give us 9=x

*If you are allowed to use a graphing calculator, you can put the equation into the graph by hitting the y= button and going to the table (2nd, Graph). This makes everything 100x easier.

Your welcome :)

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H₀: μ₁ - μ₂ = 0

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(–2975, 175)

Do not reject H₀

Step-by-step explanation:

Hello!

The objective of this experiment is to test if the salaries of elementary school teachers are equal in two districts. You can test this trough the population means of the salaries of the teachers if they are either equal or different or directly test if the difference between the salaries of the two districts is cero or not, symbolically: μ₁ - μ₂ = 0

Remember, in the null hypothesis is usually stated the known information, is the "no change" premise and always carries the = symbol.

The hypothesis is:

H₀: μ₁ - μ₂ = 0

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You have two normally distributed variables and you are studying the difference of the means. You can use a pooled Z to make the interval, the formula is:

X[bar]₁-X[bar]₂ ± Z_{1-\alpha /2}*(√(σ₁²/n₁+σ₂²/n₂)

Since the test is two-tailed and at a signification level of 5% I've made the interval at the complementary confidence level of 95% so that I can use it to decide over the hypothesis.

X[bar]₁-X[bar]₂ ± Z_{1-\alpha /2}*(√(σ₁²/n₁+σ₂²/n₂)

Z_{1-\alpha /2} = Z_{0,975} = 1,96

[28900-30300 ± 1.96*(√((2300)²/15+(2100)²/15)]

[-1400 ± 1576,15]

[-2976.15;176,15]

Since I've approximated to two decimal units in the intermediate calculations, the values ​​differ slightly, but the interval is:

(–2975, 175)Now, since the 0 is contained in the Confidence interval, the decision is to not reject the null hypothesis. In other words, the difference in average salaries between the two districts is cero.

I hope it helps!

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