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2 years ago

Paula pays 19.92 for 2.4 of walnuts. What is the price per pound of walnuts?

Mathematics

2 answers:

Verizon [17]2 years ago

5 0

Answer:

Step-by-step explanation:

She pays 19.2 for 2.4 walnuts

Price of 1 walnut = 19.92÷2.4 = 8.3

Andru [333]2 years ago

3 0

Answer:

$8.30

Step-by-step explanation:

Paula paid 19.2 for 2.4 pounds of walnuts

Price of 1 walnut = 19.92 and 19.92 ÷ 2.4 = 8.3

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Answer:

The standard equation of the sphere is $(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53$

Step-by-step explanation:

From the question, the end point are (3,-2,4) and (7,12,4)

Since we know the end points of the diameter, we can determine the center (midpoint of the two end points) of the sphere.

The midpoint can be calculated thus

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})$

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Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})$

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Midpoint = $(\frac{10 }{2}, \frac{10}{2}, \frac{8 }{2})\\$

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Now, we will determine the distance (diameter) of the sphere

The distance is given by

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To find the radius, r

From $Radius = \frac{Diameter}{2}$

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∴ $Radius = \sqrt{53}$

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Radius of the sphere is $\sqrt{53}$

The equation of a sphere of radius r and center $(h,k,l)$ is given by

$(x-h)^{2} + (y-k)^{2} + (z-l)^{2} = r^{2}$

Hence, the equation of the sphere of radius $\sqrt{53}$ and center $(5, 5, 4)$ is

$(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = \sqrt{(53} )^{2}$

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