3 years ago

Find the zeros : x(x^2+13x+40)

1 answer:

3 0

The zeros are x= 0,-5,-8. the zeros are the x values where the graph intersects the x-axis. to find the zeros, you have to replace y with zero then solve for x.

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Answer:

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Step-by-step explanation:

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How to evaluate the expression

noname [10]

$[(-72) \div (-2)]^3 - (-7) \times (-10)$

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mixas84 [53]

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