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Fynjy0 [20]
3 years ago
13

what is the factorization of 81a6 - 100? (9a2 − 10)(9a3 10) (9a2 − 10)(9a3 − 10) (9a3 − 10)(9a3 10) (9a3 − 10)(9a3 − 10)

Mathematics
2 answers:
Leokris [45]3 years ago
7 0
The given expression, 81a^6 - 100, is a difference of two squares. The first term 81a^6 is a square of 9a³. The second term, 100, is a square of 10. The factors of the given expression is therefore, (9a³ - 10) x (9a³ + 10).
liraira [26]3 years ago
6 0

Answer:The factorization of 81a^6-100=(9a^3+10)(9a^3-10)


Step-by-step explanation:

Given algebraic expression:81a^6-100

This can be written in the form of square as (9a^3)^2-10^2

By using identity, a^2-b^2=(a+b)(a-b) , the above polynomial can be rewritten as

(9a^3)^2-10^2=(9a^3+10)(9a^3-10)

Therefore the factorization of 81a^6-100=(9a^3+10)(9a^3-10)


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