Question

what is the factorization of 81a6 - 100? (9a2 − 10)(9a3 10) (9a2 − 10)(9a3 − 10) (9a3 − 10)(9a3 10) (9a3 − 10)(9a3 − 10)

Answer 1

The given expression, 81a^6 - 100, is a difference of two squares. The first term 81a^6 is a square of 9a³. The second term, 100, is a square of 10. The factors of the given expression is therefore, (9a³ - 10) x (9a³ + 10).

Answer 2

Answer:The factorization of $81a^6-100=(9a^3+10)(9a^3-10)$

Step-by-step explanation:

Given algebraic expression:$81a^6-100$

This can be written in the form of square as $(9a^3)^2-10^2$

By using identity, $a^2-b^2=(a+b)(a-b)$ , the above polynomial can be rewritten as

$(9a^3)^2-10^2=(9a^3+10)(9a^3-10)$

Therefore the factorization of $81a^6-100=(9a^3+10)(9a^3-10)$