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quester [9]
3 years ago
9

PLEASE I NEED HELP QUICKLY!!! Find the solution for the given system of equations in the form (x,y). ​ -x+y=8 7x+3y=-6

Mathematics
1 answer:
natka813 [3]3 years ago
7 0

<u>Answer:</u>

The answer D is correct.

<u>Step-by-step explanation:</u>

-x + y = 8 ⇒ ( 1 )

7x + 3y = - 16 ⇒ ( 2 )

y = 8 + x ⇒ ( 3 )

Let us take equation 2 and let us replace y with (8+x).

Let us solve and find the value of x.

7x + 3y = -16

7x + 3 ( 8 + x ) = - 16

7x + 24 + 3x = -16

10x + 24 = -16

10x = -16 - 24

10x = -40

<h3>x = (-4)</h3>

And now let us find the value of y.

For that, let us use equation (3)

Here, we have to replace x with -4 to find the value of y.

y = 8 + x

y = 8 - 4

<h3>y = 4</h3>

Now we have to the answers in the form ( x , y )

Let us write.

( x , y ) ⇒ ( -4 , 4 )

Let me know if you have any other questions. :-)

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c)\\\\x^2+8x+5=0\\\\x^2+8x=-5\\\\x^2+8x+4^2=-5+4^2\\\\(x+4)^2=11\\\\ x+4=\pm\sqrt{11}\\\\\underline{x=\pm\sqrt{11}-4\approx-7.32\ or\ -0.68}\\\\\\x)\\\\x^2+22x-15=0\\\\x^2+22x=15\\\\x^2+22x+11^2=15+11^2\\\\(x+11)^2=136\\\\x+11=\pm\sqrt{136}\\\\\underline{x=\pm\sqrt{136}-11\approx-22.66\ or\ 0.66}

e)\\\\x^2-7x+10=0\\\\x^2-7x=-10\\\\x^2-7x+(\frac72)^2=-10+(\frac72)^2\\\\x^2-7x+(\frac72)^2=-10+(\frac72)^2\\\\(x-\frac72)^2=-\frac{20}4+\frac{49}4\\\\ (x-\frac72)^2=\frac{29}4\\\\x-\frac72=\pm\sqrt{\frac{29}4}\\\\ \underline{x=\pm\frac{\sqrt{29}}2+\frac72\approx6.19\ or\ 0.81}\\\\\\f)\\\\x^2+5x-2=0\\\\x^2+5x=2\\\\x^2+5x+(\frac52)^2=2+(\frac52)^2\\\\(x+\frac52)^2=2+6.25 \\\\x+\frac52=\pm\sqrt{8.25}\\\\\underline{x=\pm\sqrt{8.25}-\frac52\approx-5.37\ or\ 0.37}

g)\\\\x^2+9x-4=0\\\\x^2+9x=4\\\\x^2+9x+(\frac92)^2=4+(\frac92)^2\\\\(x+\frac92)^2=4+20.25\\\\x+\frac92=\pm\sqrt{24.25}\\\\\underline{x=\pm\sqrt{24.25}-4.5\approx-9.42\ or\ 0.52}

h)\\\\x^2-3x-6=0\\\\x^2-3x=6\\\\x^2-3x+(\frac32)^2=6+(\frac32)^2\\\\(x-\frac32)&^2=6+2.25\\\\x-\frac32=\pm\sqrt{8.25}\\\\ \underline{x=\pm\sqrt{8.25}+1.5\approx4.37\ or-1.37}

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