Mark received £ 132
<em><u>Solution:</u></em>
Given that £440 is divided between David, Mark & Henry
Let "d" be the share of david
Let "m" be the share of mark
Let "h" be the share of henry
Total amount is 440
Therefore,
share of david + share of mark + share of henry = 440
d + m + h = 440 ------- eqn 1
<em><u>David gets twice as much as Mark</u></em>
d = 2m ----- eqn 2
<em><u>Mark gets three times as much as Henry</u></em>
m = 3h
------ eqn 3
<em><u>Substitute eqn 2 and eqn 3 in eqn 1</u></em>
Thus Mark received £ 132
Answer:
question 1: B
question 2: AB: 7 BC: 8 CD: 7 DA: 8
(pls mark brainliest)
Answer:
Let the vectors be
a = [0, 1, 2] and
b = [1, -2, 3]
( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.
Let the cross product be another vector c.
To find the cross product (c) of a and b, we have
![\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C0%261%262%5C%5C1%26-2%263%5Cend%7Barray%7D%5Cright%5D)
c = i(3 + 4) - j(0 - 2) + k(0 - 1)
c = 7i + 2j - k
c = [7, 2, -1]
( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:
c / | c |
Where | c | = √ (7)² + (2)² + (-1)² = 3√6
Therefore, the unit vector is
![\frac{[7,2,-1]}{3\sqrt{6} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5B7%2C2%2C-1%5D%7D%7B3%5Csqrt%7B6%7D%20%7D)
or
[ 
, 
, 
]
The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:
[ 
, 
, 
]
In conclusion, the two unit vectors are;
[ , , ]
and
[ , , ]
<em>Hope this helps!</em>
6 + 9x.....a common factor in both terms is 3
3(2 + 3x) <==
Answer:
2,3,6,7
Step-by-step explanation: Standard form is Ax+By=C
Number one and 4 are in point slope form. Number 5 has no y.
