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Alenkinab [10]
4 years ago
12

. Question 1.1. What is the first step in solving x2 + 2x + 3 = 0 by completing the square?. (Points : 1). Factor the left side.

. . Add 1 to each side of the equation.. . Divide both sides of the equation by 2.. . Subtract 3 from each side of the equation..
Mathematics
2 answers:
Assoli18 [71]4 years ago
6 0
U r going to subtract 3 from each side of the equation....leaving you with :
x^2 + 2x = -3
Arturiano [62]4 years ago
6 0
The first step to solving an equaiton of the form<span>ax2+bx+c = 0</span>is by completing the square by first dividing by a, giving<span>x2+bx/a+c/a = 0 
then subtract c/a to both sides.

</span>In this regard, the first step to the equation is to C. <span>. Subtract 3 from each side of the equation..</span>
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Sam bought 2 1/4 pounds of Swiss cheese and 1 1/2 pounds of cheddar at the deli. How many pounds of cheese did Sam buy altogethe
DerKrebs [107]
2 1/4 + 1 1/2 

2 + 1 = 3
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3 years ago
Which linear function represents the table
My name is Ann [436]

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Step-by-step explanation:

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3 years ago
Read 2 more answers
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GenaCL600 [577]
We know that

At sea level, the height is 0 and
the pressure is 98 kilopascals

At 1000 ft, the height is 1000 and
the pressure <span>decreases about 11.41%

</span>i(100%-11.41%)/100----> (0.8859)

therefore
1) at 1000 ft--------> the pressure is 98*(0.8859)----------> 86.82 kilopascals
2) at 2000 ft--------> the pressure is 86.82*(0.8859)-------> 76.91 kilopascals
3) at 3000 ft--------> the pressure is 76.91*(0.8859)-------> 68.14 kilopascals
4) at 4000 ft---------> the pressure is 68.14*(0.8859)-------> 60.36 kilopascals


the answer is
<span>The pressure at an altitude of 4000 m is about </span>60.36 kilopascals
7 0
3 years ago
A frightened child is restrained by her mother as the child slides down a frictionless playground slide. If the force on the chi
MissTica

Answer:

Step-by-step explanation:

Given

Restrained Force F=116 N

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Distance moved d=1.9 m

Work done by all the forces is equal to change in Kinetic Energy of Object i.e. by gravity force, Normal force and Applied Force

\Delta K.E.=W_g+W_f+W_N

30=W_g-F\cdot d

30=W_g-116\cdot 1.9

W_g=250.4 J

(b)In absence of applied force thus

work done by gravity will be equal to  change in kinetic Energy

change in Kinetic Energy=210 J

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Answer:The area of the walkway around is 26 x + 16 as the sum of two terms

Step-by-step explanation:

3 0
3 years ago
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