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melisa1 [442]
2 years ago
6

A crate of bananas has a mass of 674.8 dekagrams. What is the mass of the crate of bananas in centigrams? Use the metric table t

o help answer the question. Metric Table kilo- hecto- deka- unit deci- centi- milli- 1,000 100 10 1 0.1 0.01 0.001 0.6748 centigrams 6.748 centigrams 67,480 centigrams 674,800 centigrams
Mathematics
2 answers:
Trava [24]2 years ago
3 0

Answer:

77777373

Step-by-step explanation:

because u add all and cretin for the movies

Harlamova29_29 [7]2 years ago
3 0

Answer:

674,800

Step-by-step explanation:

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Find an equation of variation in which y varies jointly as x and z and inversely as the product of w and​ p, where yequalsstartf
leva [86]

To solve this problem you must apply the proccedure shown below:

1. You have that y varies jointly as x and z and inversely as the product of w and​ p. Therefore, you can write the following equation, where k is the constant of proportionality:

y=k(\frac{xz}{wp} )

2. Now, you must solve for the constant of proportionality, as following:

k=\frac{ywp}{xz}

3. Susbtiute values:

y=\frac{7}{28} \\ x=7\\ z=4\\ w=7\\ p=8

k=\frac{(\frac{7}{28})(7)(8))}{(7)(4)}  =0.5

4. Substitute the value of the constant of proportionality into the equation:

y=0.5(\frac{xz}{wp})

The answer is: y=0.5(\frac{xz}{wp})

7 0
3 years ago
Verify the following identity and show steps<br><br> (Cos2 θ)/(1+sin2 θ)= (cot θ-1)/(cot θ+1)
Paul [167]

Answer:

Verified below

Step-by-step explanation:

We want to show that (Cos2θ)/(1 + sin2θ) = (cot θ - 1)/(cot θ + 1)

In trigonometric identities;

Cot θ = cos θ/sin θ

Thus;

(cot θ - 1)/(cot θ + 1) gives;

((cos θ/sin θ) - 1)/((cos θ/sin θ) + 1)

Simplifying numerator and denominator gives;

((cos θ - sin θ)/sin θ)/((cos θ + sin θ)/sin θ)

This reduces to;

>> (cos θ - sin θ)/(cos θ + sin θ)

Multiply top and bottom by ((cos θ + sin θ) to get;

>> (cos² θ - sin²θ)/(cos²θ + sin²θ + 2sinθcosθ)

In trigonometric identities, we know that;

cos 2θ = (cos² θ - sin²θ)

cos²θ + sin²θ = 1

sin 2θ = 2sinθcosθ

Thus;

(cos² θ - sin²θ)/(cos²θ + sin²θ + 2sinθcosθ) gives us:

>> cos 2θ/(1 + sin 2θ)

This is equal to the left hand side.

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5 0
2 years ago
What is the radius of a circle whose equation is x2 + y2 + 8x – 6y + 21 = 0?
s344n2d4d5 [400]

Answer:

2 units

Step-by-step explanation:

The given equation of the circle is:

x^{2} + y^{2}+8x-6y+21=0

The general equation of the circle is:

x^{2} + y^{2}+2gx+2fy+c=0

Comparing the given equation with the general equation we can say:

g = 4

f = -3

c = 21

The formula for radius of the circle is:

radius=\sqrt{g^{2} +f^{2} -c }

Using these values of the given circle, we get:

radius=\sqrt{(4)^{2}+(-3)^{2}-21}\\\\radius=\sqrt{4}\\\\radius=2

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Tema [17]
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GrogVix [38]

Answer:

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Step-by-step explanation:

6 0
1 year ago
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