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uysha [10]
4 years ago
10

Determine the greatest common factor of the following 4x2y2, 3xy4, 2xy2

Mathematics
1 answer:
Ludmilka [50]4 years ago
6 0
Well we solve each of these individually.
For the first one 4x2y2 we will apply the exponent rule of a^b * a^c = a^b + c.
So...
2^2 * 4xy
4 * 4xy, apply the same exponent rule.
4^2xy > 16xy (GCF)

For 3xy4 it is very simple.
Simply multiply the numbers 3 * 4 = 12 or 12xy (GCF)

For 2xy2 apply the exponent rule we used before above.
2 * 2 = 2^1 + 1 = 2^2 > 2^2xy = 4xy(GCF)

Therefore we have 
<span>4x2y2 = 16xy
</span><span>3xy4 = 12xy
</span><span>2xy2 = 4xy

Out of all of these, which has the greatest GCF? :)</span>
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Utlizando el siguiente diagrama encuentra el valor de h
Nastasia [14]

Answer:

h=78.4

Step-by-step explanation:

2/1.25 = h/49

Cross multiplication

1.25h = 2x49

1.25h=98

h= 78.4

                   CHECK:

         2/1.25 = 1.6

        78.4/49=1.6

7 0
3 years ago
8x+4y=-20 and -4x-8y=-20 solve each system by substitution
True [87]
8x + 4y = -20
4y = -20 - 8x
y = -5 -2x

-4x - 8y = -20
-4x - 8(-5-2x) = -20
-4x + 40 + 16x = -20
12x = -60
x = -5

8(-5) + 4y = -20
-40 + 4y = -20
4y = 20
y = 5
4 0
4 years ago
An axiom in Euclidean geometry states that in space, there are at least points that do
oksian1 [2.3K]

An axiom in Euclidean geometry states that in space, there are <u>2</u> points that <u>lie on the same line</u>.

This is called the two-point postulate. According to Euclidean geometry, in space, there are at least two points, and through these points, there exists exactly one line. This means that there is only one single line that could pass between any two points. This is a mathematical truth. It is known as an axiom because an axiom refers to a principle that is accepted as a truth without the need for proof.

6 0
4 years ago
Read 2 more answers
I need four lines that are parallel because I am doing a math project which is tainted glass
barxatty [35]

Answer:

Okay so what do we do

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
You have relatives living in the United Kingdom and in France. Suppose that you have purchased a prepaid phone card with a value
maxonik [38]

Answer:

a) 0.23x+0.21y=75

b) (For the Graph see the attached picture).

A possible solution for the inequality 0.23x+0.21y\leq75 would be any point inside the shaded region of the graph. For example (150,175) This is 150 minutes to the United Kingdom and 175 minutes to France.

0.23x+0.21y\leq75

0.23(150)+0.21(175)\leq75

34.5+36.75\leq75

71.25\leq 75

this inequality is true, so the number of minutes used for the United Kingdom and to France is valid.

Step-by-step explanation:

a)

In order to solve this problem, we must first set our variables:

x= Minutes to the United Kingdom.

y= Minutes to France

The greatest amount of money you can spend is $75 and each minute will cost $0.23 when calling to the United Kingdom and $0.21 when calling to France. So we can use this information to build our equation:

0.23x+0.21y=75.

b) So first, we need to convert our equation into an inequality where the total amount of money spent must be less than $75, so our inequality is:

[tex}0.23x+0.21y\leq75[/tex]

so now we can proceed and graph. This is graphed exactly as you would graph a regular linear equation. You need to find two points on the graph that will satisfy the equation. Plot them and then connect them with a straight line. For example:

First, let's solve the equation for y:

0.23x+0.21y=75

we start by moving the 0.23x to the other side of the equation so we get:

0.21y=-0.23x+75

and next we divide both sides of the equation into 0.21 so we get:

y=\frac{-0.23x+75}{0.21}

which yields:

y= -1.095x+357.14

next we need to pic an x-value so we can find the first ordered pair. Let's say I pick x=0. So we get:

y= -1.095x+357.14

y= -1.095(0)+357.14

y=357.14

so our first point is (0, 357.14)

And we can follow the same procedure for the second point. Let's say I pick x=1. In that case our second point is (1, 354.04). We can now plot them. Once the graph is drawn, we need to shade it, for which we will pick an ordered pair to the left and an ordered pair to the right of the line. For the left region let's pick the point (0,0) and for the right of the graph, let's pick the point (150,357).

So let's test the inequality for these two points:

First, let's use the point (0,0)

0.23x+0.21y\leq75

0.23(0)+0.21(0)\leq75

0\leq75

This proves that the left side of the graph is the side to be shaded. We can still use the other point and see what we qet:

(150, 357) and let's use it on our inequality:

0.23x+0.21y\leq75

0.23(150)+0.21(357)\leq75

109.47\leq75

Is a false statement, so only the region on the left will contain the possible number of minutes to do the phone calls to the UK and France.

A possible solution for the inequality 0.23x+0.21y\leq75 would be any point inside the shaded region of the graph. For example (150,175) This is 150 minutes to the United Kingdom and 175 minutes to France.

0.23x+0.21y\leq75

0.23(150)+0.21(175)\leq75

34.5+36.75\leq75

71.25\leq 75

This is a true statement so the possible solution is correct.

6 0
3 years ago
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