All categories

3 years ago

DUE VERY SOON URGENT PLEASE HELP!!

Mathematics

1 answer:

Alla [95]3 years ago

7 0

The values of x are

1. x = 32°,

2. x = 15°,

3. x = 49°,

4. x = 65°,

Explanation:

The angle made by any right angle is 90° and the angle made by a straight line is 180°. These are the main equations required to solve the values of x. The first 2 are right angles and the last 2 are straight lines. So the sum of the components within that right angle is 90° and for a straight line is 180°.

For diagram 1; 2x° + x° - 6° = 90°, 3x° = 90° + 6° = 96°, x = $\frac{96}{3}$ = 32°.

For diagram 2; 4x° + 3° + x° + 12° = 90°, 5x° = 90° - 15° = 75°, x = $\frac{75}{5}$ = 15°.

For diagram 3; x° + 33° + 2x° = 180°, 3x° = 180° - 33 = 147°, x = $\frac{147}{3}$ = 49°.

For diagram 4; 2x° + 1° + x° - 16° = 180°, 3x° = 180° + 15° = 195°, x = $\frac{195}{3}$ = 65°.

You might be interested in

What is the distance from City B to City D?

Alecsey [184]

Answer:

35km please follow me broo

3 0

3 years ago

Which of the following is NOT true about the tails in a distribution?

Alla [95]

Answer:

The answer is D: The inequality symbol in the alternative hypothesis points away from the critical region.

Step-by-step explanation:

We usually have a one-tailed and two-tailed tests. Examples of a one-tailed test are the left-tailed and the right tailed test. These tests are referred to as one-tailed tests because the critical region or rejection region is located in only one tail. The critical region of a left or right tailed test is that region that correlate with the rejection region and is usually located in extreme left or right tail. Furthermore, tails in a distribution are usually the extreme critical regions also known as the rejection regions which are bound by critical values. However there is nothing that suggests the statement in Option D when talking about tails in a distribution.

6 0

4 years ago

Conrad has 6 more marbles than Rory. If r represents the numbers of marbles that Rory has, which expression represents the numbe

beks73 [17]

Answer:

r+6

Step-by-step explanation:

r = marbles that Rory has

r+6 = marbles that Conrad has

3 0

3 years ago

A fast-food company is interested in knowing the probability of whether a customer viewed an advertisement for their new special

lord [1]

Answer:

45% probability that a randomly selected customer saw the advertisement on the internet or on television

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a customer saw the advertisement on the internet.

B is the probability that a customer saw the advertisement on television.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a customer saw the advertisement on the internet but not on television and $A \cap B$ is the probability that the customers saw the advertisement in both the internet and on television.