Angie buys 1 software package and 3 months of game play
Kenny buys 1 software package and 4 months of game play
price of each software package = $20
total cost = $117
cost of one month game play = ?
let y is the cost of one month play
Angie buys 3 months game play and paid $20 = 20 + 3y
Kenny buys 4 months game play and paid $20 = 20 + 4y
total cost of both is $117
So the equation becomes,
(20 + 3y) + (20 + 4y) = 117
7y + 40 = 117
7y = 117 - 40
7y = 77
dividing with 7 on both sides, we get
y = 11
so, $11 is the cost of one month game play

5 0

3 years ago

A class has 6 boys and 15 girls. What is the ratio of boys to girls

Gnoma [55]

$the \ ratio \ is : \\ \\ boys \ to \ girls = 6:15= 2:5$

4 0

3 years ago

Read 2 more answers

Solve the initial value problem. dy/dt = 1 + 6/t , t > 0, y = 8 when t = 1

nordsb [41]

$\displaystyle\frac{dy}{dt} = 1 + \frac{6}{t}\ \Rightarrow\ dy = \left( 1 + \frac{6}{t}\right) dt\ \Rightarrow\int 1\, dy = \int \left( 1 + \frac{6}{t}\right) dt \ \Rightarrow \\ \\
y = t + 6\ln|t| + C. \text{ But $t\ \textgreater \ 0$ so }y = t + 6\ln t + C. \\ \\ 
y(1) = 8\ \Rightarrow\ 8 = 1 + 6 \ln 1 + C \ \Rightarrow\ C = 7 \text{ so } \\ \\
y(t) = t + 6\ln t + 7$

5 0

3 years ago

andrew11 [14]

Answer:

the digit two is in tens... so a) is the answer

4 0

3 years ago