Answer:
262,143
Step-by-step explanation:
- 1
- 1+2
- 3+4
- 7+8
- 15+16
- 31+32
- 63+64
- 127+128
- 255+256
- 511+512
- 1023+1024
- 2047+2048
- 4095+4096
- 8191+8192
- 16,383+16,384
- 32,767+32,768
- 65,535+65,536
- 131,071+131,072
=262,143
Answer:
<u>2 </u>sack of cement is required to cover Joel's entire floor.
Step-by-step explanation:
Given:
A sack cement can cover area = 45 sq. ft
Length of Joel floor = 8 ft
Width of Joel Floor = 7 ft
We will first find the Area of Joel's Floor
Area is the Product of length and width.
Area of the Floor =
Substituting the values we get;
Area of the Floor =
Now Given:
1 sack of cement cover area = 45 sq ft
Number of sack cement required to cover area = 56 sq. ft.
By Using Unitary method we will find the same.
∴ Number of sack cement required =
Since Sack of cement cannot be in point value hence we can say 2 sack cement is required.
Hence we can say 2 sack of cement is required to cover Joel's entire floor.
Answer:
1/6
Step-by-step explanation:
1/2 + 1/3 + x =1
5/6 + x = 1
x = 1 - 5/6
x = 1/6
You can find the answer by multiplying 0.875 * 32
so 28...