The wall area is the product of the room perimeter and the room height:
A₁ = (2*(12.5 ft + 10.5 ft))*(8.0 ft) = 368 ft²
The window and door area together is
A₂ = 2*((4 ft)*(3 ft)) + (7 ft)*(3 ft) = 45 ft²
The area of one roll of wallpaper is
A₃ = (2.5 ft)*(30 ft) = 75 ft²
Then the number of rolls of wallpaper required will be
1.1*(A₁ - A₂)/A₃ ≈ 4.74
5 rolls of wallpaper should be purchased.
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As a practical matter, not much of the window and door area can be saved. The rolls are 30 inches wide, but the openings are 36 inches wide. Some will likely have to be cut from two strips. The strips will have to be the full length of the wall, and the amount cut likely cannot be used elsewhere. If the window and door area cannot be salvaged, then likely ceiling(5.4) = 6 rolls will be needed (still allowing 10% for matching and waste).
About 190% because its almost two times the original number
I hope that answers your question
Answer:
15 m
Step-by-step explanation:
First split the shape into a square and a triangle, then find the area of the square by multipliyng the sides to get.
Next find the length of the traignel by subtracting 3 from 9 to get for then find the area of the triangle by multiplying 4 by 3 to get 12 then divide by 2 to get the area which is 6.
Finally add the 9 to the 6 to get 15
3 * 3 = 9
9 - 3 = 4
4 * 3 = 12/2 = 6
6+9=15
