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Simora [160]
3 years ago
6

7th question plsssss​

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
5 0

convert to exponential form

8^x=512=8^3

x=3

The logarithm of 512 to the base 8=3

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Peter works part time for 3 hours every day and Cindy works part time for 2 hours every day.
Dmitriy789 [7]

Answer:

a. We can say that P > C, where 'P' represents Peter's earnings and 'C' represents Cindy's earnings.

Given that P = 3h and C = 2h, where h =$4.50. We can say also that 3h > 2h.

b. If Cindy wants to earn at least $14 a day working two hours. Then:

2h ≥  $14

To solve the problem, we just need to solve for 'h':

h ≥ $7

Therefore, se should earn more or equal to $14 per hour.

4 0
4 years ago
Read 2 more answers
At Chestatee Middle School, 120 students are in choir. The ratio of girls to boys in choir is 5:3.
Serhud [2]
Let the total number of students be x;
given that the ratio of girls to boys is 5:3, then:
The equation that represents the number of girls will be:
5/8x
The equation that represents the number of boys will be :
3/8x
The equation that represents the total number of boys and girls will be:
5/8x+3/8x

B] suppose there are g number of girls. The  equation that represents the number of boys in terms of number of girls will be:
(ratio of boys to girls)×(number of girls)
3/5×(g)
=(3g)/5


8 0
3 years ago
Read 2 more answers
The Jones family income is $42,000 a year (net pay), which is $3,500 a month.
Pachacha [2.7K]
Wow this is gonna take me a while
4 0
4 years ago
Pls helpp im failing
nydimaria [60]

Answer:

-41.6

Step-by-step explanation:

6 0
3 years ago
Please help, I’ll mark your answer as brainliest.
Brrunno [24]

Answers:

(f \circ g)(x) = \sqrt{36x^2+96x+65}\\\\\\(f \circ g)(2) = \sqrt{401}\\\\

========================================================

Work shown for part 1

f(x) = \sqrt{x^2-2x+2}\\\\f(g(x)) = \sqrt{(g(x))^2-2(g(x))+2}\\\\f(g(x)) = \sqrt{(-6x-7)^2-2(-6x-7)+2}\\\\f(g(x)) = \sqrt{36x^2+84x+49+12x+14+2}\\\\f(g(x)) = \sqrt{36x^2+96x+65}\\\\(f \circ g)(x) = \sqrt{36x^2+96x+65}\\\\

----------------------------------

Work shown for part 2

(f \circ g)(x) = \sqrt{36x^2+96x+65}\\\\(f \circ g)(2) = \sqrt{36(2)^2+96(2)+65}\\\\(f \circ g)(2) = \sqrt{401}\\\\

6 0
2 years ago
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