Question

What is the following product? Assume d≥0. 3√d*3√d*3√d d d^3 3(3√d) √3d

Answer 1

Answer:

It's A) d

Step-by-step explanation:

Answer 2

we are given

$\sqrt[3]{d} *\sqrt[3]{d}*\sqrt[3]{d}$

we can use property of exponents

$\sqrt[n]{a}*\sqrt[n]{b} *\sqrt[n]{c}=\sqrt[n]{a*b*c}$

so, we can write it as

$\sqrt[3]{d} *\sqrt[3]{d}*\sqrt[3]{d}=\sqrt[3]{d*d*d}$

$\sqrt[3]{d} *\sqrt[3]{d}*\sqrt[3]{d}=\sqrt[3]{d^3}$

we can simplify it

and we get

$\sqrt[3]{d} *\sqrt[3]{d}*\sqrt[3]{d}=d$................Answer