Answer:
There is no option in the question given.
However, In logic and probability theory, two events are mutually exclusive or disjoint if they cannot both occur at the same time. A clear example is the set of outcomes of a single coin toss, which can result in either heads or tails, but not both.
1. Given that e<span>vents A and B are dependent, P(A)=20%, P(BIA)=25%. What is P(A and B)?
P(BIA)=[P(A and B)]/P(A)
it follows then that:
P(A and B)=P(A)*P(BIA)
P(A)=0.2
P(BIA)=0.25
hence
P(A and B)=0.2*0.25=0.05=5%
2. Given that </span><span> P(A) =12%, P(B)=48% and P(A or B)=50%. What is P(A and B)?
P(A or B)=P(A)+P(B)-P(A and B)
but
P(A)=12%, P(B)=48%, P(A and B)=50%
thus
P(A or B)=12%+48%-50%
simplifying the above we obtain:
P(A or B)=60%-50%=10%
</span>
Answer:
SOH CAH TOA.....Cosine=adj/hyp...... __cosX=16/30___
SOH CAH TOA,,,,,, Tangent= opp/adj-------- Tan X=36/27
Step-by-step explanation:
Answer:
![\frac{dy}{dx}=-[(\frac{5x+24}{36x-6x^2})]](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%3D-%5B%28%5Cfrac%7B5x%2B24%7D%7B36x-6x%5E2%7D%29%5D)
Step-by-step explanation:
Given function:
y =
we know
= ln(A) - ln(B)
thus,
y = 
or
also,
ln(Aⁿ) = n × ln(A)
thus,
y = 
therefore,
![\frac{dy}{dx}=[(\frac{3}{2})\times\frac{1}{(6-x)}\times(0 - 1)] - [ (\frac{2}{3})\times\frac{1}{x}\times1]](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%3D%5B%28%5Cfrac%7B3%7D%7B2%7D%29%5Ctimes%5Cfrac%7B1%7D%7B%286-x%29%7D%5Ctimes%280%20-%201%29%5D%20-%20%5B%20%28%5Cfrac%7B2%7D%7B3%7D%29%5Ctimes%5Cfrac%7B1%7D%7Bx%7D%5Ctimes1%5D)
or
or
![\frac{dy}{dx}=-[(\frac{3(3x)+2\times2(6-x)}{2(6-x)\times(3x)})]](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%3D-%5B%28%5Cfrac%7B3%283x%29%2B2%5Ctimes2%286-x%29%7D%7B2%286-x%29%5Ctimes%283x%29%7D%29%5D)
or
Could you take a clearer picture
