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sesenic [268]
4 years ago
9

HELP FAST all point (50) + brainiest

Mathematics
1 answer:
maks197457 [2]4 years ago
8 0

Answer:

The correct option is 1.

Step-by-step explanation:

Let the amount invested in utility bound be x. So, the amount invested in saving account is (10000-x).

It is given that the yearly income from the two investments is same.

\text{9\% of x}=\text{6\% of (10000-x)}

\frac{9}{100}\times x=\frac{6}{100}\times (10000-x)

\frac{9x}{100}=600-\frac{6x}{100}

\frac{9x}{100}+\frac{6x}{100}=600

\frac{15x}{100}=600

15x=60000

x=4000

The amount invested in utility bound is $4000.

10000-x=10000-4000=6000

The amount invested in saving account is $6000.

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