Answer:
Step-by-step explanation:
Given tq equation of the height reached by the rocket as y=-16x^2+235x+133
The velocity of the object at its maximum height is zero
v = dy/dx = 0(at max height)
v =-32x +235
0 =-32x+235
x = 235/32
x = 7.34
Hence the rocket will reach its maximum height after 7.34seconds
Answer:
c
d
e
Step-by-step explanation:
c) 2(50%)=75%
d) 1=0.75
e) 1=0.75
sry my mistake wrong quesrion
Using the pythagorean identity, we can find the value of sin(A)
cos^2(A) + sin^2(A) = 1
(12/13)^2 + sin^2(A) = 1
144/169 + sin^2(A) = 1
sin^2(A) = 1 - 144/169
sin^2(A) = 169/169 - 144/169
sin^2(A) = (169 - 144)/169
sin^2(A) = 25/169
sin(A) = sqrt(25/169)
sin(A) = 5/13
Which is then used to find tan(A)
tan(A) = sin(A)/cos(A)
tan(A) = (5/13) divided by (12/13)
tan(A) = (5/13)*(13/12)
tan(A) = (5*13)/(13*12)
tan(A) = 5/12
The final answer is 5/12
Answer:
I think that you need to add obvoiusly.
12351 Thats what I got. But Im not sure if its correct. I hope his helps
Step-by-step explanation: