let the solution be 
let the solutions be a = 3, b = 1
is the equation with consistent value.
Answer:
f(-5) = 4(-5) + 1 = -20 + 1 = -19
f(-1) = 4(-1) + 1 = -4 + 1 = -3
f(2) = 4(2) + 1 = 8 + 1 = 9
f(3) = 4(3) + 1 = 12 + 1 = 13
f(5) = 4(5) + 1 = 20 + 1 = 21
Answer:
-7v² - 57v - 2
Step-by-step explanation:
-7v² - 49v - 2 - 8v
-7v² - 57v - 2
<em>Answer:</em>
Complete proof is written below.
Facts and explanation about the segments shown in question :
- As BC = EF is a given statement in the question
- AB + BC = AC because the definition of betweenness gives us a clear idea that if a point B is between points A and C, then the length of AB and the length of BC is equal to the length of AC. Also according to Segment addition postulate, AB + BC = AC. For example, if AB = 5 and BC= 7 then AC = AB + BC → AC = 12
- AC > BC because the Parts Theorem (Segments) mentions that if B is a point on AC between A and C, then AC > BC and AC>AB. So, if we observe the question figure, we can realize that point B lies on the segment AC between points A and C.
- AC > EF because BC is equal to EF and if AC>BC, then it must be true that the length of AC must greater than the length segment EF.
Below is the complete proof of the observation given in the question:
<em />
<em>STATEMENT REASON </em>
___________________________________________________
1. BC = EF 1. Given
2. AB + BC = AC 2. Betweenness
3. AC > BC 3. Def. of segment inequality
4. AC > EF 4. Def. of congruent segments
<em />
<em>Keywords: statement, length, reason, proof</em>
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Answer:
C. 139°
Step-by-step explanation:
Given:
m<A = 62°
m<B = 77°
Required:
Find m<1
Solution:
Since ∆ABC is similar to ∆DEF, therefore:
<A ≅ <D, which means m<D = 62°
<B ≅ <E, which means m<E = 77°
<C ≅ <F
Therefore, based on exterior angle theorem:
m<1 = m<D + m<E
m<1 = 62° + 77° (substitution)
m<1 = 139°
