Answer:
Y= -4x+ 21
Step-by-step explanation:
There are two of them.
I don't know a mechanical way to 'solve' for them.
One can be found by trial and error:
x=0 . . . . . 2^0 = 1 . . . . . 4(0) = 0 . . . . . no, that doesn't work
x=1 . . . . . 2^1 = 2 . . . . . 4(1) = 4 . . . . . no, that doesn't work
x=2 . . . . . 2^2 = 4 . . . . . 4(2) = 8 . . . . . no, that doesn't work
x=3 . . . . . 2^3 = 8 . . . . . 4(3) = 12 . . . . no, that doesn't work
<em>x=4</em> . . . . . 2^4 = <em><u>16</u></em> . . . . 4(4) = <em><u>16</u></em> . . . . Yes ! That works ! yay !
For the other one, I constructed tables of values for 2^x and (4x)
in a spread sheet, then graphed them, and looked for the point
where the graphs of the two expressions cross.
The point is near, but not exactly, <em>x = 0.30990693...
</em>If there's a way to find an analytical expression for the value, it must involve
some esoteric kind of math operations that I didn't learn in high school or
engineering school, and which has thus far eluded me during my lengthy
residency in the college of hard knocks.<em> </em> If anybody out there has it, I'm
waiting with all ears.<em>
</em>
Answer:
2400 in^3
Step-by-step explanation:
Tyler asks for a fish tank for his birthday. The task he wants is a rectangular prism 20 inches long, 10 inches wide, and 12 inches tall. How much water will the fish tank hold?
the capacity of the tank can be determined by calculating the volume of the tank
volume of a prism = length x width x height
20 x 10 x 12 = 2400 in^3
If something is placed the way these places are(directly NORTH and the park is SOUTH) all you have to do is add your two values, lining up your decimal points. 1.75
+.6
2.35
Let me know if this helps by making me your brainliest answer
