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Answer:
(2a +b)·(13a^2 -5ab +b^2)
Step-by-step explanation:
The factorization of the difference of cubes is a standard form:
(p -q)^3 = (p -q)(p^2 +pq +q^2)
Here, you have ...
so the factorization is ...
(3a -(a -b))·((3a)^2 +(3a)(a -b) +(a -b)^2) . . . . substitute for p and q
= (2a +b)·(9a^2 +3a^2 -3ab +a^2 -2ab +b^2) . . . . simplify a bit
= (2a +b)·(13a^2 -5ab +b^2) . . . . . . collect terms
What you need to know for this case is that the sum of the internal angles of a triangle is 180 °
We then have the following equation that is given by:
(2x) + (3x) + (4x) = 180
Clearing x we have:
9x = 180
x = 180/9
x = 20
Therefore we have:
m∠A = (40) °
m∠B = (60) °
m∠C = (80) °
Answer:
B) m∠B = 60 °
Answer:
y=5x-10
Step-by-step explanation:
y+10=5x
y=5x-10
Answer:
x=-11
y=-1
Step-by-step explanation:
x=4y-7
2x+9y=-31
2(4y-7)+9y=-31
8y-14+9y=-31
17=-31+14
17y=-17
y=-1
x=4(-1)-7
x=-11