F(x)=(x – 5)(x+3)(x-1) Degree?
1 answer:
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Answer:
112.569 ( D )
Step-by-step explanation:
Applying the estimated Regression Equation
y = b1X1 + b2X2 + a
b1 = ((SPX1Y)*(SSX2)-(SPX1X2)*(SPX2Y)) / ((SSX1)*(SSX2)-(SPX1X2)*(SPX1X2)) = 596494.5/635355.88 = 0.93884
b2 = ((SPX2Y)*(SSX1)-(SPX1X2)*(SPX1Y)) / ((SSX1)*(SSX2)-(SPX1X2)*(SPX1X2)) = 196481.5/635355.88 = 0.30925
a = MY - b1MX1 - b2MX2 = 149.25 - (0.94*61.31) - (0.31*193.88) = 31.73252
y = 0.939X1 + 0.309X2 + 31.733
For x1 ( age ) =39, and x2(weight) =143
y = (0.93884*39) + (0.30925*143) + 31.73252= 112.569
where
Sum of X1 = 981
Sum of X2 = 3102
Sum of Y = 2388
Mean X1 = 61.3125
Mean X2 = 193.875
Mean Y = 149.25
attached is the Tabular calculation of the required values needed for estimated regression equation
Answer:
4,099 and 5,011
Step-by-step explanation:
This problem can be solved by taking options one by one.
Option (1) : 4,099
Digit in ones place = 9
The value of the digit in tens place = 90
. It is correct.
Option (2) : 4,110
Digit in one places = 0
The value of the digit in tens place = 10
It is incorrect.
Option (3) : 5,909
Digit in one places = 9
The value of the digit in tens place = 0
It is again incorrect.
Option (4) : 5,011
Digit in one places = 1
The value of the digit in tens place = 10
. It is correct.
Hence, in option (a) and (d), the he ones place is 1/10 the value of the digit in the tens place.