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3 years ago

Find the sum (6y – 2) + (5y + 5)

Mathematics

2 answers:

slavikrds [6]3 years ago

7 0

Answer:

11 y + 3

Step-by-step explanation:

(6y-2) + (5y+5)

Add 6y and 5y

11y - 2 + 5

Add -2 and 5

11 y + 3

Flura [38]3 years ago

6 0

Answer: 11y + 3

Step-by-step explanation:

Add the integers never add an integer with a a regular number. Then just add the regular numbers and put the two problems together based on what it is if it’s subtraction you put 11y - 3 and so on

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Explain how the graph of y=|x+1|-2 will differ from the graph of y=|x|.

Natali5045456 [20]

$\bf ~~~~~~~~~~~~\textit{function transformations}\\\\\\f(x)= A( Bx+ C)+ D\\\\~~~~y= A( Bx+ C)+ D\\\\f(x)= A\sqrt{ Bx+ C}+ D\\\\f(x)= A(\mathbb{R})^{ Bx+ C}+ D\\\\f(x)= A sin\left( B x+ C \right)+ D\\\\--------------------\\\\\bullet \textit{ stretches or shrinks horizontally by } A\cdot B\\\\\bullet \textit{ flips it upside-down if } A\textit{ is negative}$

$\bf ~~~~~~\textit{reflection over the x-axis}\\\\\bullet \textit{ flips it sideways if } B\textit{ is negative}\\~~~~~~\textit{reflection over the y-axis}\\\\\bullet \textit{ horizontal shift by }\frac{ C}{ B}\\~~~~~~if\ \frac{ C}{ B}\textit{ is negative, to the right}$

$\bf ~~~~~~if\ \frac{ C}{ B}\textit{ is positive, to the left}\\\\\bullet \textit{ vertical shift by } D\\~~~~~~if\ D\textit{ is negative, downwards}\\\\~~~~~~if\ D\textit{ is positive, upwards}\\\\\bullet \textit{ period of }\frac{2\pi }{ B}$

with that template in mind,

$\bf y=\stackrel{A}{1}|\stackrel{B}{1}x\stackrel{C}{+1}|\stackrel{D}{-2}$

so is really just |x| but shifted some,

C/B = 1/1 = +1, horizontally to the right by 1 unit.

D = -2, vertically downwards by 2 units.

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3 years ago

What is the measure of RCP?

Bezzdna [24]

Answer:

Step-by-step explanation:

15+15+27+27

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2 years ago

Help with two step equations with fractions.........<br> 2/3x=6

pashok25 [27]

Multiply 2/3 by the reciprocal, 3/2, on both sides.

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3 years ago

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alexandr402 [8]

Answer:

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Step-by-step explanation:

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r-ruslan [8.4K]

Use pythagorena theorme

D= $\sqrt{(x1-x2)^{2}+(y1-y2)^{2}}$
NOTE: x1 and x2 means the first x and second x, not x^1 and x^2

points given are
(1,1)
(5,6)
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y1=1
x2=5
y2=6
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D= $\sqrt{(-4)^{2}+(-5)^{2}}$
D= $\sqrt{16+25}$
D= $\sqrt{41}$
6.403

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3 years ago

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