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lisov135 [29]
3 years ago
14

Janie was given (-2, 3) as the endpoint of a line segment and (0,1) as its midpoint, which ordered pair should Janie choose as h

e other endpoint?

Mathematics
1 answer:
MaRussiya [10]3 years ago
8 0
When given two end points of a segment say for example (X1,Y1) and (X2,Y2) to get the midpoint of the line or the segment we use the formula,
 midpoint =( (X1+X2)/2 , (Y1+Y2)/2 )
therefore in our case the midpoint is (0,1)
hence, (-2 + X2)/ 2 = 0, thus X2 = 2
        and (3 + Y2)/ 2= 1 , thus Y2 = -1
Therefore the other end point will be (2,-1). Thus none of the above paper can be used as the other end point.
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2 years ago
Help me please ;-;-;-;-;​
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Answer:

y = -5

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
2+1.25f=10−2.75f solve for f
Inga [223]
Hey there!

2 + 1.25f = 10 - 2.75f
Add 2.75f to both sides.

1.25f + 2.75f = 4f

4f + 2 = 10
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Divide both sides by 4 to solve for f.

f = 2

I hope this helps!
6 0
3 years ago
What is the factor of x³ 5x² 2x 24?
Delvig [45]

The factors of the expression x³-5x²-2x+24 are: (x+2)(x-3)(x-4)

<h3>What is a factor?</h3>

A factor is a number that completely divides another number.

In other words, since the result may be divided by the two whole numbers we are multiplying, they are factors of the result if multiplying two whole numbers produces a result.

The numbers that can divide a number exactly are called factors.

There is none left over after division as a result.

The numbers you multiply together to produce another number are called factors.

A factor is hence the division of another number.

So, we have the expression: x³-5x²-2x+24

Now, calculate the factors as follows:

x³-5x²-2x+24

We already know that: P(-2) = 0

Hence, x+2 is a factor.

Now, other factors are: x² - 7x + 12

x² + 4x + 3x + 12

(x - 3)(x - 4)

Therefore, the factors of the expression x³-5x²-2x+24 are: (x+2)(x-3)(x-4)

Know more about the factors here:

brainly.com/question/24351176

#SPJ4

Correct question:
What is the factor of x³-5x²-2x+24?

3 0
1 year ago
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