Actually the answers A since t is for text messages and it costs .15 and m is minutes and costs .07 so we add those two together to he .15t+ .07m then there's a discount of 2.50 so we subtract. So our final equation is .15t + .07m - 2.50 = C
Which data set has an outlier? 25, 36, 44, 51, 62, 77 3, 3, 3, 7, 9, 9, 10, 14 8, 17, 18, 20, 20, 21, 23, 26, 31, 39 63, 65, 66,
umka21 [38]
It's hard to tell where one set ends and the next starts. I think it's
A. 25, 36, 44, 51, 62, 77
B. 3, 3, 3, 7, 9, 9, 10, 14
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Let's go through them.
A. 25, 36, 44, 51, 62, 77
That looks OK, standard deviation around 20, mean around 50, points with 2 standard deviations of the mean.
B. 3, 3, 3, 7, 9, 9, 10, 14
Average around 7, sigma around 4, within 2 sigma, seems ok.
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
Average around 20, sigma around 8, that 39 is hanging out there past two sigma. Let's reserve judgement and compare to the next one.
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Average around 74, sigma 8, seems very tight.
I guess we conclude C has the outlier 39. That one doesn't seem like much of an outlier to me; I was looking for a lone point hanging out at five or six sigma.
Answer:
15
Step-by-step explanation:
Calculation for What is a reasonable estimate of the number of gallons of gas Karl used
Estimated number of gallons used=619.5 miles/41 miles
Estimated number of gallons used=15
Therefore the reasonable estimate of the number of gallons of gas Karl used is 15
Answer:
I think that the altimeter would read as '0'. Positive readings would show that she was above sea level and negative readings we would show that she was below sea level. I hope that this helps
Answer:
Step-by-step explanation:
From the table we have to:
Probability of syrup is 0.96
Probability of waffles and syrup is 0.32
P (Waffles | Syrup) = P (Waffles and syrup) / P (syrup)
So:
If this equality is met, the probabilities are dependent, if on the contrary
P (Wafles | Syrup) = P (Wafles) then are independent probabilities.
So we have to:
The probabilities are dependent.
