Let f be the fathers age and let s be the sons age
f = 60 s = 30
when f = 45
s = 15 which is only a third if his fathers age
when f = 40
s = 10 which is a quarter of his fathers age
therefore when his father was 4 times his age, the son was 10
Answer:
Approximately 68% of the apples have diameters that are between 7.08cm and 7.78cm.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
Approximately 68% of the measures are within 1 standard deviation of the mean.
Approximately 95% of the measures are within 2 standard deviations of the mean.
Approximately 99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean of 7.43cm, standard deviation of 0.35cm.
What percentage of the apples have diameters that are between 7.08cm and 7.78cm?
7.43 - 0.35 = 7.08 cm.
7.43 + 0.35 = 7.778 cm.
Within 1 standard deviation of the mean, so approximately 68% of the apples have diameters that are between 7.08cm and 7.78cm.
Answer:
(a+2b)(3x+2y)
Step-by-step explanation:
3ax+2ay+6bx+4by = a(3x+2y)+2b(3x+2y) = (a+2b)(3x+2y)
Answer:
for me the answer is letter B.
Answer:
Order 2.
Step-by-step explanation:
