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tensa zangetsu [6.8K]
4 years ago
6

So uhhh part 2 uhhhh whats 9+10?

Mathematics
2 answers:
Veronika [31]4 years ago
7 0

Answer:

19

Step-by-step explanation:

Rzqust [24]4 years ago
5 0

Answer:

19

Step-by-step explanation:

9 + 10 = 19

This is due to addition.

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Use the order of operations to evaluate the expression 4×(3/4 - 1/2) +3×6​
jekas [21]

Answer:

19

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

Step-by-step explanation:

<u>Step 1: Define</u>

4 × (3/4 - 1/2) + 3 × 6

<u>Step 2: Evaluate</u>

  1. (Parenthesis) Subtract:                                                                                     4 × 1/4 + 3 × 6
  2. Multiply:                                                                                                             1 + 3 × 6
  3. Multiply:                                                                                                             1 + 18
  4. Add:                                                                                                                   19
4 0
3 years ago
What number gives a result of −5 when 8 is subtracted from the quotient of the number and 5?
shusha [124]
-5 = x/5 - 8
3 = x/5
15 = x

Check:
15/5 = 3 - 8 = -5 :)
3 0
3 years ago
Fill in the missing number.<br><br> __% of 80 = 60
Shtirlitz [24]

Answer:

it would be 75% :))

4 0
2 years ago
Read 2 more answers
ΔABC is similar to ΔAXY by a ratio of 5:3. If BC = 25, what is the length of XY?
Allisa [31]

Answer:

I think its XY=15.

Step-by-step explanation:

7 0
4 years ago
uestion 2 The points A(-2, 3,-1), B(0, 5, 2) and C(-1, -2, 1) lies on the same plane. (a) Find the vector equation of the plane.
RoseWind [281]

Answer with explanation:

Equation of Plane having Direction cosines A, B and C passing through points, p, q and r is

⇒A (x-p)+B(y-q)+C(z-r)=0

The plane passes through the points A(-2, 3,-1), B(0, 5, 2) and C(-1, -2, 1).

→A(x+2)+B(y-3)+C(z+1)=0----------(1)

→A(0+2)+B(5-3)+C(2+1)=0

2 A +2 B+3 C=0

→A(-1+2)+B(-2-3)+C(1+1)=0

A -5 B+2 C=0

\Rightarrow \frac{A}{4+15}=\frac{B}{3-4}=\frac{C}{-10-2}\\\\\Rightarrow \frac{A}{19}=\frac{B}{-1}=\frac{C}{-12}=k\\\\A=19 K,B=-K, C=-12K

Substituting the value of A , B and C in equation (1)

⇒19 K(x+2)-K(y-3)-12 K(z+1)=0

⇒19 x +38 -y +3-12 z-12=0

⇒19 x -y -12 z +29=0, is the required equation of Plane in Cartesian form.

⇒(19 i -j -12 k)(xi +y j+z k)+29=0 ,is the required  vector equation of the plane.

8 0
3 years ago
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