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saw5 [17]
2 years ago
10

Your company takes orders over the phone. The company’s average call time is 4.6 minutes. The graph below shows 4 calls and the

difference between the call time and the company’s average call time. For these 4 calls, what is the mean difference between the call times and the company’s average call time, rounded to the nearest 0.1 minute?
(Note: A negative difference indicates the call is shorter than the average.)

Mathematics
1 answer:
Rina8888 [55]2 years ago
6 0

The mean difference between the call times and the company’s average call time is 0.4.

<h3>How to calculate the mean?</h3>

It should be noted that mean also means average.

Based on the information given, the mean of the numbers will be:

= -2.32 + -1.55 + 4.79 + 0.68 / 4

= 1.6/4

= 0.4

Therefore, the mean difference between the call times and the company’s average call time is 0.4.

Learn more about mean on:

brainly.com/question/1136789

#SPJ1

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A manufacturing company measures the weight of boxes before shipping them to the customers. If the box weights have a population
NikAS [45]

Answer:

<u>The probability that the average weight of the boxes will exceed 94 pounds  is 43.25%</u>

Step-by-step explanation:

1. Let's review the information provided to answer the question correctly:

Mean of the population of box weights = 90 pounds

Standard deviation of the population of box weights = 24 pounds

Sample size = 36 boxes

2. What is the probability that the average weight of the boxes will exceed 94 lb?

For answering this question, we will use the z-scores table.

For using the correct z-score, we should use the correct standard deviation. In this case, we have that:

94 - 90 = 4 pounds above the mean.

4 pounds are 4/24 of the standard deviation,

therefore, simplifying:

4/24 = 1/6 = 0.1666......and we'll round to 0.17

z-score is 0.17 because 4 pounds is 1/6 of the standard deviation (24).

The probability of a z-score is 0.5675, but in this case we're asked by a weight over 94 pounds, not under 94 pounds, thus:

1 - 0.5675 = 0.4325

<u>The probability that the average weight of the boxes will exceed 94 pounds  is 43.25%</u>

8 0
3 years ago
Which answer would be correct
tatuchka [14]
The answer I believe is b

5 0
3 years ago
What are the coordinates of point P? Please help show steps it’s urgent!
Vlad [161]

Answer:

A (2, -8/5)

Step-by-step explanation:

The answer would be A I believe. This is because to get from C to D, it would be going down 6 and to the right by 10.

To make CP = 3/5CD. We multiply how much we move by 3/5:

-6 * 3/5 = -18/5 (note that the 6 would be negative because its going down)

and 10 * 3/5 = 6

Then we add these values to the coordinates of C:

(-4 + 6,  2 - 18/5) =

(2, -8/5). So A would be the answer.

7 0
4 years ago
The expression (y-20)(y5)3 is equivalent to ya. What is the value of a?
Leno4ka [110]

Answer:

y¹⁵-20y¹⁴

Step-by-step explanation:

I'm going to assume that your problem looks like this

(y-20)(y^5)^3

(x^n)^y=x^{n*y}

which means we have

(y-20)*y^{15}\\\\y^{16}-20y^{15}=ya\\\\*y^{15}-20y^{14}=a

5 0
3 years ago
The distance on a bike path between Westfield and Southborough is 46 mi. Tracey leaves Westfield heading to Southborough cycling
ipn [44]

Answer: 2 hr.

Explanation: Think back to rate of change. <em>d</em> = <em>rt</em>, <em>r</em> = <em>d/t</em>, <em>t</em> = <em>d/r</em>. In this case, we will be using <em>d</em> = <em>rt</em>. Mph would be <em>r</em>, rate, so you would categorize 15 mph and 8 mph under rate. <em>t</em> should represent the time each cyclist traveled. Tracey's and Emma's distance, <em>d</em>, would be the same as their mph, hence Tracey's being 15<em>t</em> and Emma's would be 8<em>t</em>. When you add Tracey's distance plus Emma's distance, you end up with 46 mi. Now, you need to combine like terms, which should look like 15<em>t</em> + 8<em>t </em> = 46. Add 15 and 8 to get 23, so it should be 23<em>t</em> = 46 now. Then, divide both sides of the equation by 23 and now you should have your answer, <em>t</em> = 2 hr.

8 0
3 years ago
Read 2 more answers
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