I believe it is either fish of plants (Most likely plants).
Answer:
Oxygen, carbon dioxyde
Explanation:
After oxygen was distributed to somatic cells, there are higher concentraion of carbon dioxyde. Therefore, it will move out from our cell to be exhaled by lungs. Vice versa for oxygen
Answer:
The answer is C.
Explanation:
Net Primary Productivity is a term that is used to express the difference between CO2 that is taken in by the plant with photosynthesis minus CO2 that the plant releases.
The two forest sites given in the example may not have the same biodiversity and the same species of plants so we can't be sure of option B.
Again for the same reasons, we can't be sure of option D because we do not know the specific plant species in each forest since they are in different areas.
Option A can be ruled out for the same reasons, the lack of information about the forest sites, since we do not know the death rate of the plants in either of the forests.
Option C can be true because forest A has a higher net primary productivity rate which can be an indication of lower respiratory activity hence lower CO2 production, resulting in the given higher net primary productivity.
I hope this answer helps.
Answer:
1/8 (12.5%)
Explanation:
An autosomal recessive disease is an inherited disease in which an individual need to receive both defective alleles at the same gene <em>locus</em> to be expressed in the phenotype. In this case, both parents are carriers of the recessive mutant allele associated with the sickle cell anaemia trait, thereby both parents are heterozygous, ie., each parent has one copy of the normal allele 'H' and one copy of the defective mutant allele 'h' associated with this condition. In consequence, their first child has a 1/4 (25%) chance of having sickle-cell anaemia. Moreover, the chance of having a girl is 1/2 and the chance of having a boy is 1/2, thereby the final chance of having a girl sickle cell anaemia individual is 1/4 x 1/2 = 1/8 (12.5%).
- Parental cross for sickle cell anaemia trait = Hh x Hh >>
- F1 = 1/4 HH (normal); 1/2 Hh (normal); 1/4 hh (sickle cell anaemia) >>
- Sex proportion of sickle cell anaemia individuals = 1/8 female sickle cell anaemia individuals + 1/8 male sickle cell anaemia individuals (1/8 + 1/8 = 1/4)
