Triangles with height
and base
, with
have area
.
Such cross sections with the base of the triangle in the disk
(a disk with radius 5) have base with length

i.e. the vertical (in the
plane) distance between the top and bottom curves describing the circle
.
So when
, the cross section at that point has base

so that the area of the cross section would be 6^2/2 = 18.
In case it's relevant, the entire solid would have volume given by the integral

Since the string has already two 2, then we will compute the whole number of strings whose length is 4, over the alphabet {0,1}:

There is then 16 such strings.
Radius = Diameter ÷ 2 = 10 ÷ 2 = 5mm
<u>
Find Volume: </u>
Volume= πr²h
Volume = π (5)² (6) = 471.24mm³ (Nearest hundredth)
<u>Find Surface Area:</u>
Surface area = 2πr² + 2πrh
Surface area = 2π(5)² + 2π(5)(6) = 345.58 mm²
Answer: Volume = 471.24mm³ , Surface area = 345.58 mm²
Standard form = 3.0098 × 10 power 4
Significant figures = 30100
The answer would be 1.23 that is the answer