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luda_lava [24]
3 years ago
9

1 question pleasee i need this asap!! thank you :D

Mathematics
1 answer:
nydimaria [60]3 years ago
6 0
The correct answer is:  [A]:  " x = 6 " or  " x = - 9 " .
________________________________________________________
Explanation:
________________________________________________________
Given the following equation:
________________________________________________________
   
   " x² + 3x – 54 = 0 " ;  Solve for "x" ; 
_____________________________________________________
Check if the part of the equation on the "left-hand side" can be "factored":

   " x² + 3x – 54 " ; 

→  We see the " + 3x " and the " – 54 "

Factors of " -54 " that add up to " +3" ;

Let us try:  " -9, 6" ;   →  " -9 + 6 = -3 " ;  →  " -3 ≠ +3 ;

Let us try:  " 9, -6" ;   →  " 9 + (-6) = 9 – 6 = 3 " ;   YES!
       →   {that is:  " +9 , -6 "} ; 


So, we can rewrite the entire equation:

→  " (x + 9)(x – 6) = 0 " ;

→  " x = -9 " ;  or,  " x = 6 " ; which is:  

→  Answer choice:  [A]:  " x = 6 "  or  " x = - 9 " .
______________________________________________________
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Step-by-step explanation:

Given the expression

\left(x^5+y^5\right)\div \left(x+y\right)

\mathrm{Apply\:factoring\:rule:\:}x^n+y^n=\left(x+y\right)\left(x^{n-1}-x^{n-2}y+\:\dots \:-\:xy^{n-2}\:+\:y^{n-1}\right)\:\quad \quad \mathrm{n\:is\:odd}

x^5+y^5=\left(x+y\right)\left(x^4-x^3y+x^2y^2-xy^3+y^4\right)

=\frac{\left(x+y\right)\left(x^4-x^3y+x^2y^2-xy^3+y^4\right)}{x+y}

Cancel the common factor: x+y

=x^4-x^3y+x^2y^2-xy^3+y^4

Thus,

\frac{x^5+y^5}{x+y}=x^4-x^3y+x^2y^2-xy^3+y^4

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